Answer:
Explanation:
Q₂ is at the origin and Q₁ is at 12 cm on x -axis
Force between Q₁ and Q₂
= K x Q₁ x Q₂ / .12 where k is a constant equal to 9x 10⁹
Force F = 9 x 10⁹ x Q₁ x Q₂ / .12²
= 625 x 10⁹ x Q₁Q₂ N
This is the force each one exerts on other . So electric force on Q₂ due to Q₁ is 625 x 10⁹ x Q₁Q₂ N . Its direction is towards left as both will repel each other.
b)
Electric field due to charge Q₂ at - 2 cm
= 9 x 10⁹ x Q₂ / .02²
= 22500 x 10⁹ x Q₂ N/C , towards left .
Electric field due to charge Q₁ at - 2 cm
= 9 x 10⁹ x Q₁ / .14²
= 459.18 x 10⁹ x Q₁ N/C , towards left
As both the fields are to the same direction
Net field = 75 x 10⁹ x Q₂ + 459.18 x 10⁹ x Q₁
10⁹ ( 22500 x Q₂ + 459.18 x Q₁ ) N/C .
Direction will be towards left.
