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dangina [55]
3 years ago
10

Two charges and are separated by 10cm on the x- axis. Q2 is at the origin and Q1 is 12cm to the right.

Physics
1 answer:
Evgen [1.6K]3 years ago
8 0

Answer:

Explanation:

Q₂ is at the origin and Q₁ is at 12 cm on x -axis

Force between Q₁ and Q₂

= K x Q₁ x Q₂ / .12 where k is a constant equal to 9x 10⁹

Force F = 9 x 10⁹ x Q₁ x Q₂ / .12²

= 625 x 10⁹ x Q₁Q₂ N

This is the force each one exerts on other . So electric force on Q₂ due to Q₁ is 625 x 10⁹ x Q₁Q₂ N . Its direction is towards left as both will repel each other.

b)

Electric field due to charge Q₂ at - 2 cm

= 9 x 10⁹ x Q₂ / .02²

= 22500 x 10⁹ x Q₂ N/C , towards left .

Electric field due to charge Q₁ at - 2 cm

= 9 x 10⁹ x Q₁ / .14²

= 459.18 x 10⁹ x Q₁  N/C , towards left

As both the fields are to the same direction

Net field = 75 x 10⁹ x Q₂ + 459.18 x 10⁹ x Q₁

10⁹ ( 22500 x Q₂ + 459.18  x Q₁ ) N/C .

Direction will be towards left.

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Which of these processes in the water cycle occur at a very high rate, to cause a hurricane?
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Answer: d. evaporation and condensation

Water vapor is known as the main fuel that moves the hurricane. The evaporation will cause the water vapor to move upward carrying the latent heat of condensation. The vapor will cause condensation later. If both happen at a very high rate, the wind produced can become a hurricane. 
5 0
3 years ago
In billiards, the 0.165 kg cue ball is hit toward the 0.155 kg eight ball, which is stationary. The cue ball travels at 5.8 m/s
Damm [24]

Answer:

another ball velocity = 3.92 m/s and with 30° clockwise from initial direction

Explanation:

given data

mass m1 = 0.165 kg

mass m2 = 0.155 kg

before collision velocity v1 = 5.8 m/s

before collision velocity v2 = 0

angle =  35.0° from initial direction

after collision 1st ball velocity v3 = 3.2 m/s

to find out

after collision another ball velocity v4

solution

we consider here ball move in x axis and after collision 1st ball move upside of x axis with angle 35 degree and other ball move downside with x axis with angle θ

so from conservation of momentum we say

m1v1 = m1v3cos35 + m2v4cosθ   with x axis    .............1

m1v3sin35 = m2v4sinθ                   with y axis  .............2

so from 1 equation

0.165 × 5.8 = 0.165(3.2)cos35 + 0.155(v4)cosθ

v4 cosθ  = 3.38                                            .................3

form 2 equation

0.165(3.2)sin35 = 0.155(v4)sinθ  

v4 sinθ = 1.95                                              ......................4

so magnitude of another ball velocity is square and adding equation 3 and 4

another ball velocity = √(3.39²+1.96²)

another ball velocity = 3.92 m/s

and direction is tanθ = 1.96/3.39

θ = 30° clockwise from initial direction

3 0
3 years ago
As you may well know, placing metal objects inside a microwave oven can generate sparks. Two of your friends are arguing over th
Fofino [41]

Answer:

5.04\cdot 10^8 A

Explanation:

The work function of the metal corresponds to the minimum energy needed to extract a photoelectron from the metal. In this case, it is:

\phi = 3.950\cdot 10^{-19}J

So, the energy of the incoming photon hitting on the metal must be at least equal to this value.

The energy of a photon is given by

E=\frac{hc}{\lambda}

where

h is the Planck's constant

c is the speed of light

\lambda is the wavelength of the photon

Using E=\phi and solving for \lambda, we find the maximum wavelength of the radiation that will eject electrons from the metal:

\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{3.950\cdot 10^{-19} J}=5.04\cdot 10^{-7}m

And since

1 angstrom = 10^{-15}m

The wavelength in angstroms is

\lambda=\frac{5.04\cdot 10^{-7} m}{10^{-15} m/A}=5.04\cdot 10^8 A

3 0
3 years ago
I need help for the first 3 plz.
madam [21]
1) hypothesis
2) data
3) method

I think these are correct.
7 0
3 years ago
Read 2 more answers
A 500kg car is driving through a neighborhood at 20m/s. Then the car hits a speed bump which causes it to slow to 15m/s. What wa
lawyer [7]

Based on the formula for calculating impulse, the impulse of the speed bump to the car is 2500 Ns.

<h3>What is the impulse of the speed bump?</h3>

  • Impulse = change in momentum
  • momentum = mass * velocity

Change in momentum = mu - mv

where u is initial velocity

v is final velocity

Impulse = 500 * 20  - 500 * 15

Impulse = 2500 Ns

Therefore, the impulse of the speed bump to the car is 2500 Ns.

Learn more about impulse at: brainly.com/question/297527

5 0
3 years ago
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