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Brums [2.3K]
3 years ago
12

PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!

Physics
1 answer:
Leya [2.2K]3 years ago
5 0

Answer:

c

Explanation:

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The data table shows the cause of unintentional death for various age groups; what can you infer about the 15-24 age group?
Blizzard [7]

Answer:

D) They most likely died from not wearing a seatbelt.

Explanation:

Their death was caused by a "motor vehicle" (that's what MV stands for in this case). The most logical answer would be D.

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3 years ago
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23 is 2% of what<br> number?
8_murik_8 [283]

Answer:

1;150

Explanation:

2% × ? = 23

? =

23 ÷ 2% =

23 ÷ (2 ÷ 100) =

(100 × 23) ÷ 2 =

2,300 ÷ 2 =

1,150;

7 0
3 years ago
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Liquid flows through a 4.0 cm diameter pipe at 1.0 m/s. there is a 2.0 cm diameter restriction on the line. what is the velocity
Vanyuwa [196]
To determine the velocity in the restriction, we need to remember the law of conservation of mass where mass in should be equal to the mass out since mass cannot be created or destroyed. For this system, mass flow rate in is equal to mass flow rate out. We do as follows:

Mass flow rate in = Mass flow rate out
density (volumetric flow rate in) = density (volumetric flow rate out)

Since the liquid in and out are the same, then density would be cancelled.
(volumetric flow rate in) = (volumetric flow rate out)
Area in x velocity in = Area out x velocity out
velocity out = area in x velocity in / area out
velocity out = π (4/2)^2 (1.0) / π (2/2)^2
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4 0
3 years ago
What is another name for the range of motion in your joint
Neporo4naja [7]

Answer:Gliding

Explanation:

Because it’s an ball and socket joint

3 0
3 years ago
Water from a leaking tap begins to fall into
Amanda [17]

Answer:

It will take 20,000 seconds to get a pressure of 200Pa at the bottom of the tank.

Explanation:

The pressure at the bottom of the tank will be

P = \dfrac{Mg}{A}

where M is the mass of the water, and A is the base area of the tank.

The base area of the tank is

A = 0.5m* 2m = 1m^2,

and if we want the pressure at the bottom to be 200pa, then it must be that

200Pa = \dfrac{M(10m/s^2)}{1m^2},

solving for M we get:

M = 20kg\\

which is the required mass of the water in the tank.

Now, the tank fills at a rate of 2 drops per second or

2 (0.05g)/s = 0.10g/s = 0.0001kg/s

since each drop weights 0.05g.

Therefore, the time t it takes to collect 20kg of water will be

t = 20kg \div \dfrac{0.0001kg}{s}

t = 2*10^5s

which is 55.56 hours or 2 days and 7.56 hours.

Thus, it will take 20,000 seconds to get a pressure of 200Pa at the bottom of the tank.

7 0
3 years ago
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