(6a²b⁶)³
(6a²b⁶)(6a²b⁶)(6a²b⁶)
(6 · 6 · 6)(a² · a² · a²)(b⁶ · b⁶ · b⁶)
216a⁶b¹⁸
Answer:
x = 12
Step-by-step explanation:
You can use power of a point to solve this problem in the scenario where two secants intersect in the exterior of a circle. You get the equation:
(x + 5 + 7)(7) = (x + 1 + 8)(8)
You can simplify to get:
(x + 12)(7) = (x + 9)(8)
7x + 84 = 8x + 72
84 = x + 72
x = 12
9+1=10, 10+6=16 because that is and would be the only logical answer
Answer:
24 students per mile
Step-by-step explanation:
Given in the question,
Length of rectangle for building university = 75 miles
Width of rectangle for building university = 25 miles
Total area:
Length x Width
= 75 x 25
= 1875 miles²
Only 70% of the buildings at this university are used for instruction
70% of 1875 miles²
70/100 x 1875
= 1312.5 miles²
32,125 students are enrolled at this university
So,
1312.5 miles² = 32,125 students
1 mile = 32,125/1312.5
= 24 students per mile