PV = nRT —> n = PV/RT
P = 2.90 atm
V = 4.80 L
R = 0.08206 L atm / mol K
T = 62.0 + 273 = 335 K (make sure you convert from celsius to kelvin)
n = (2.90 • 4.80) / (0.08206 • 335) = 0.506 moles of gas
Answer:
Ka = 1.5 × 10⁻⁵
Explanation:
Butyric acid is a weak acid that ionizes according to the following equation:
CH₃-CH₂-CH₂-COOH(aq) ⇄ CH₃-CH₂-CH₂-COO⁻(aq) + H⁺(aq)
We can find the value of the acid dissociation constant (Ka) using the following expression:
where
[H⁺] is the molar concentration of H⁺
Ca is the initial molar concentration of the acid
We can find [H⁺] from the pH.
pH = -log [H⁺]
[H⁺] = antilog -pH = antilog -2.71 = 1.95 × 10⁻³ M
Then,
There are two hydrogen atoms in one molecule of water.
The answer is B) 2
Answer: Hydrogen belongs to group 1 metal elements in the periodic table.
Explanation:
The hydrogen is a highly active metal. It has a single electron in its valence shell and it can donate its electron to other metal atoms. Thus forming metal hydrides. The hydrogen when ignited it reacts with oxygen and burns explosively this is indicative of high reactivity and spontaneous reactivity of hydrogen atom.