Like Earth, the moon

In a 3.7- gram sample, there are______ atoms of gold

beks73 [17]

<h3>Answer:</h3>

1.1 × 10²² atoms Au

<h3>General Formulas and Concepts:</h3>

Chemistry

Atomic Structure

Reading a Periodic Table
Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<h3>Explanation:</h3>

Step 1: Define

3.7 g Au

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of Au - 196.97 g/mol

Step 3: Convert

$3.7 \ g \ Au(\frac{1 \ mol \ Au}{196.97 \ g \ Au} )(\frac{6.022 \cdot 10^{23} \ atoms \ Au}{1 \ mol \ Au} )$ = 1.13121 × 10²² atoms Au

Step 4: Check

We are given 2 sig figs. Follow sig fig rules and round.

1.13121 × 10²² atoms Au ≈ 1.1 × 10²² atoms Au

7 0

3 years ago

What two planets feud the most ?

Irina18 [472]

Fred and Ethel Mertz

8 0

3 years ago

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Answer these plz for 10 points =)

4vir4ik [10]

Explanation:

turn a paper that is wet and a alkaline is a wet tooo

4 0

3 years ago

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An unknown solid acid is either citric acid or tartaric acid. To determine which acid you have, you titrate a sample of the soli

Norma-Jean [14]

Answer:

The unknown acid is citric acid.

Explanation:

Based on the reactions:

Citric acid: H3C6H5O7(aq) + 3NaOH (aq) → 3H2O (l) + Na2C6H5O7 (aq)

Tartaric acid: H2C4H4O6 (aq) + 2NaOH (aq) → 2H2O (l) + Na2C4H4O6 (aq)

0.956g of sample if tartaric acid requires:

0.956g × (1mol / 150,087 g) = 0.006370 moles of tartaric acid. As 1 mole reacts with 2 moles of NaOH:

0.006370 moles of tartaric acid × (2 mol NaOH / 1 moles tartaric acid) = 0.0127 moles of NaOH. As the concentration of the NaOH is 0.513M:

0.0127 moles of NaOH × (1L / 0.513mol) = 0.0248L ≡ 24.8mL

Now, 0.956g of citric acid requires:

0.956g × (1mol / 192,124g) = 0.004976 moles of citric acid. As 1 mole reacts with 3 moles of NaOH:

0.004976 moles of citric acid × (3 mol NaOH / 1 moles tartaric acid) = 0.0149 moles of NaOH. As the concentration of the NaOH is 0.513M:

0.0149 moles of NaOH × (1L / 0.513mol) = 0.0291L ≡ 29.1mL

As the titration requires 29.1mL of the base, the unknown acid is citric acid.

5 0

3 years ago

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The table below shows some physical properties of two unknown samples. Physical Properties Sample Mass Solubility (in water) C 2

Vaselesa [24]

The answer would be: The two substances are not the same because the property that is independent of the amount of the sample is different.

The two substances has different solubility which is 36 g/mL and 180 g/mL. The same kind of molecule should have same density and solubility, regardless the mass of the sample. In this case, the substances are not same since it has different solubility.

4 0

4 years ago

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