The buffer will probably be destroyed by the addition of HCN.
<h3>What is buffer solution?</h3>
A weak acid and the conjugate base of the weak acid, or a weak base and the conjugate acid of the weak base, are combined to form the buffer solution, a water-based solvent solution. They withstand being diluted or having modest amounts of acid or alkali added to them without changing their pH.
Given that a 1.0 l buffer solution is 0.15 m in HCN and 0.10 m in NaCN.
We need to find a action which one destroy the buffer solution.
A buffer is a substance made of salt and a weak acid that is beneficial. From the aforementioned chemicals, HCN is a potent acid and NaCN is a salt between HF and NaCN. Therefore, the buffer will probably be destroyed by the addition of HCN.
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Answer:
3/11
Step-by-step explanation:
Answer:
95.1
Step-By-Step Explanation
78:82*100 =
(78*100):82 =
7800:82 = 95.12
Now we have: 78 is what percent of 82 = 95.12
Question: 78 is what percent of 82?
Percentage solution with steps:
Step 1: We make the assumption that 82 is 100% since it is our output value.
Step 2: We next represent the value we seek with x.
Step 3: From step 1, it follows that 100%=82
Step 4: In the same vein, x%=78
Step 5: This gives us a pair of simple equations:
$100\%=82(1)
$x\%=78(2)
Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS
(left hand side) of both equations have the same unit (%); we have
100% over x% = 82 over 78
Step 7: Taking the inverse (or reciprocal) of both sides yield
x% over 100% = 78 over 82
x = 95.12%
Therefore, 78 is 95.12% of 82
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The total distance Tracy traveled was 15,000 feet assuming each unit represents 1,000 feet.
<h3>How to calculate the total distance?</h3>
The total distance is the sum of all the distance between stops.
Partial distances:
- Home to stop 1: 2,000 feet
- Stop 1 to 2: 4,000 feet
- Stop 2 to 3: 5,000 feet
- Stop 3 to 4: 4,000 feet
- Total distance: 15,000 feet
However, the real distance would be 10.63 units based on the locations in the grid.
- d=√(0−8)^2+(7−0)^2
- d=√8^2+7^2
- d=√64+49
- d=√113 =10.63 units
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