I can give you the link for the answers
So a²+b²=c²
8²+15²=c²
64+225=c²
289=c²
±17=c
So c=17 or c=-17
2/3 times x-4 = 6
thats the answer :)
The length of q, to the nearest 10th of a centimeter is 7.6 cm.
Given in question,
In ΔOPQ,
o = 9.2 cm
p = 2.4 cm
∠Q = 37°
Cosine formula ⇒ cos θ = 
Putting the values in equation,
cos 37 = 
0.799 = 
0.799*44.16 = 90.4 - 
32.28 = 90.4 - 
= 90.4 - 32.28
= 58.12


q = 7.6 cm (to nearest 10th)
Hence, length of q is 7.6 cm.
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