Question

A 515-kg roller coaster is at the bottom of a loop with a radius of 10 m. If the speed at the

Answer 1

Answer:

20600N

Explanation:

Given parameters:

Mass of the roller coaster  = 515kg

radius  = 10m

Speed  = 20m/s

Unknown:

Force of the track pushing up on the vehicle  = ?

Solution:

The force pulling the roller coaster along the track is the centripetal force.

To find the centripetal force, use the expression below;

  F  = $\frac{mv^{2} }{r}$

where;

  m is the mass

  v is the speed

  r is the radius

Now insert the parameters and solve;

              F = $\frac{515 x 20^{2} }{10}$  = 20600N