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Effectus [21]
4 years ago
14

What is the maximum mass that can hang without sinking from a 20-cm diameter Styrofoam sphere in water? Assume the volume of the

mass is negligible compared to that of the sphere.
Physics
1 answer:
alex41 [277]4 years ago
3 0

Answer:

the maximum mass that can hang without sinking is 2.93 kg

Explanation:

Given: details:

sphere diameter  d = 20 cm

so, radius r = 10 cm  = 0.10 m

density of the Styrofoam sphere D = 300 kg/m3

sphere volume  V = \frac{4}{3} \pi r^3

                                                   =\frac{4}{3} \pi 0.10^3

                                                   =4.18*10^{-3} m^3

we know that

Density = \frac{Mass}{Volume}

mass  M = Density * Volume

                                  = (300)(4.18*10^{-3} m3)

                                  =1.25 kg

mass of the water displace = volume *density  of water

                                                 = 4.18*10^{-3} m3 * 1000

                                                 = 4.18 kg

The difference between the mass of water and mass of styrofoam is the amount of mass that the sphere can support

=4.18 kg  -1.25 kg

= 2.93 kg

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photoshop1234 [79]

Answer:

I = 20 A

Explanation:

The question says that, "A load of 6,000 C is conducted through a cross section in 5 minutes. Determining-if a current is not correct, we will find the value of?"

We have,

Charge, q = 6,000 C

Time, t = 5 minutes = 300 s

We need to find the current. We know that, the charge flowing per unit time is equal to current. So,

I=\dfrac{q}{t}\\\\I=\dfrac{6000}{300}\\\\I=20\ A

So, the current flowing through the circuit is 20 A.

7 0
3 years ago
A car of weight 6,400 N has four wheels. Each wheel has an area of
Natasha2012 [34]

Answer:

80N/cm^2

Explanation:

Given data

A car of weight 6,400N

Area= 80cm^2

The weight is distributed evenly on the 4 wheels

hence 6400/4

=1600 N

We know that

Pressure = force/Area

Pressure= 1600/80

Pressure= 20 N/cm^2

For the four wheels, the pressure is

=20*4

=80N/cm^2

6 0
3 years ago
The total momentum of two marbles before a collision is 0.06 kg-m / s. no outside forces act on the marbles. what is the total m
SpyIntel [72]
Hi my friend, since momentum is always conserved without external forces, the momentum after the collosion will still be 0.06 kg*m/s. Hope it helps☺
4 0
3 years ago
A 2-kg rock is thrown vertically upward at a speed of 3.2 m/s from the surface of the moon. If it returns to its starting point
worty [1.4K]

Answer:

1.6 m/s2

Explanation:

Let g_m be the gravitational acceleration of the moon. We know that due to the law of energy conservation, kinetic energy (and speed) of the rock when being thrown upwards from the surface and when it returns to the surface is the same. Given that g_m stays constant, we can conclude that the time it takes to reach its highest point, aka 0 velocity, is the same as the time it takes to fall down from that point to the surface, which is half of the total time, or 4 / 2 = 2 seconds.

So essentially it takes 2s to decelerate from 3.2 m/s to 0. We can use this information to calculate g_m

g_m = \frac{\Delta v}{\Delta t} = \frac{0 - 3.2}{2} = \frac{-3.2}{2} = -1.6 m/s^2

So the gravitational acceleration on the Moon is 1.6 m/s2

8 0
4 years ago
Which expression is equal to the number of grams (g) in 2.43 kilograms (kg)?
Kryger [21]

Answer:

A. 2.43 kg x 1000 g/1 kg

Explanation:

We know that the equivalence between grams and kilograms is

1 kg = 1000 g

So, if we want to convert a mass m from kg to g, we just need to multiply the value by the factor \frac{1000 g}{1 kg}.

In this problem, the mass is

m = 2.43 kg

Therefore, multiplying by the factor above, we get

m = 2.43 kg \cdot \frac{ 1000 g}{1 kg}

4 0
3 years ago
Read 2 more answers
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