The impulse imparted to the shells equals the change in the momentum:
Fav*(Delta t)= Delta m*v.
The mass change is
Delta m= n*m= (89.9shells)*(88.7g)=7.97Kg
So the average force is
F=((v)*(Delta m))/t= ((929)*(7.97))/4.84=1529.78 N
Since the velocity of the shells is much greater than the velocity of the helicopter, there is no need to use relative velocity.
Answer: P= W/t so P=50/20 =2.5 W
Answer:
$364.29
Explanation:
given,
Packing of crates per month (u)= 800
annual carrying cost of 35 percent of the purchase price per crate.
Ordering cost(S) = $ 28
D = 800 x 12 = 9600 crates/year
H = 0.35 P
H = 0.35 x $10
H = $3.50/crate per yr.
Present Total cost
= 
= 1400 + 336
= $ 1,736



Total cost at EOQ
= 
= 685.86 + 685.85
= $ 1,371.71
the firm save annually in ordering and carrying costs by using the EOQ
= $ 1,736 - $ 1,371.71
= $364.29
Explanation:
use the diagram^
horizontal velocity of the object nvr changes, it'll stay 50m/s till it hits the ground
initial vertical velocity = 0
to find the final vertical velocity, use the formula:

where u = 0m/s, a = 9.8m/s², and s = 2000m
solve for v.
for time taken to reach ground, use the formula:

where v = the value for v u calculated above, u = 0 m/s, a = 9.8m/s² and solve for t.
Answer:
15 mph
Explanation:
Velocity = Distance/time
Distance, D = velocity * time
After 2 hours, the first train would have covered a distance of:
D1 = 60 * 2 = 120 miles
The second train would have covered a distance of:
D2 = 45 * 2 = 90
The difference in the distance covered by the two trains after 2 hours is:
ΔD = D1 - D2
ΔD = 120 -90
ΔD = 30 miles
The rate at which the distance is changing, Rate = ΔD/Δt
Rate = 30/2
Rate = 15 mph