<span>This is the equation made from the problem where x=mystery number
</span><span>2x+3(x+1)=4(x-1)</span><span>
</span><span>Now let's solve for x!
</span><span>
</span><span>We start by distributing 3 into (X+1)
</span><span>
</span><span>3(x)=3x and 3(1)=3
</span><span>
</span><span>Now our equation is 2x+3x+3=4(x-1)
</span><span>
</span><span>Let's combine both x values on the left side of the equation: 2x + 3x=5x
</span><span>
</span><span>We now have 5x+3=4(x-1)
</span><span>
</span><span>Let's distribute 4 into (x-1)
</span><span>
</span><span>4(x)=4x and 4(-1)=-4
</span><span>
</span><span>Now our equation is 5x+3=4x-4
</span><span>
</span><span>subtract 3 form both sides
</span><span>
</span><span>5x=4x-7
</span><span>
</span><span>subtract 4x from both sides
</span><span>
</span><span>x=-7
</span><span>
</span><span>Yay! So the number she is thinking of is -7!</span><span>
</span>
Answer:
5+5=9and mark me as brainlestttt
-9/5 or -1.8
2 - - 3 = 5
-5 - 4 = -9
Answer:
- Library 2 charges more for each book loaned.
- Library 1 has a cheaper subscription fee.
Step-by-step explanation:
Based on the table, we can write the equation for the cost of borrowing from Library 2 using the two-point form of the equation of a line:
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
for (x1, y1) = (2, 15.50) and (x2, y2) = (8, 26) this equation becomes ...
y = (26 -15.50)/(8 -2)(x -2) +15.50 . . . . . fill in the values
y = (10.50/6)(x -2) +15.50 . . . . . . . . . . . . simplify a bit
y = 1.75x -3.50 +15.50 . . . . . . simplify more
In the above, we have x = number of books; y = cost. We can use "n" and "C" for those, respectively, as in the equation for Library 1. Then the monthly cost for Library 2 is ...
C = 12 + 1.75n . . . . . . . arranged to the same form as for Library 1
_____
Now, we can answer the questions.
Library 2 charges more for each book loaned. (1.75 vs 1.50 for Library 1)
Library 1 has a cheaper subscription fee. (10 vs 12 for Library 2)
_____
The numbers in the cost equations are ...
C = (subscription fee) + (cost per book loaned)·n
