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emmasim [6.3K]
3 years ago
13

life will not be possible on earth without the water that covers much of its surface and the air that surrounds it earth water a

nd air from each other in many ways which of the following situations represents an interaction between the atmosphere and hydrospher
Chemistry
1 answer:
Vladimir [108]3 years ago
5 0
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Every organism has a unique common name.
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Answer true

Explanation:

Every recognized species on earth (at least in theory) is given a two-part scientific name. ... These naming rules mean that every scientific name is unique. For example, if bluegill sunfish are given the scientific name Lepomis macrochirus, no other animal species can be given the same name

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A new element is discovered that is very unstable and highly reactive, and it likes to lose its one valence electron. in what gr
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In order to achieve the Octet rule and stability, the atom will lose or gain electron so that only eight electrons will be in the shell. These elements are placed in the group 1 or A of the periodic table. The group is comprised of the hydrogen and the alkali metals. 
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Cells carry out which of the following functions in an organism?
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smaller organelles

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Which of the following terms best reflects the process by which humans store memories ?
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A 45.0 mL solution of 0.0450 M hydroxylamine is extracted with 125 mL of solvent. The distribution constant for the reaction is
julia-pushkina [17]

Answer:

pH = 4.5, concentration = 0.045 M.

pH = 6.5, concentration = 0.175 M.

Explanation:

The ka for the can be calculated by using the formula below;

Ka = 10^-pka = 10^-5.960 = 1.1 × 10^-6

The concentration of hydrogen ion at pH = 4.50 can be calculated as given below;

{H^+ } = 10^-4.50 = 3.2 × 10^-5 M.

(NB=> 10 in this regards means the inverse of log).

The next step is to determine the distribution coefficient which can be calculated by using the formula below;

distribution coefficient = (partition coefficient) × ka / ka + ( concentration of Hydrogen ion,H^+).

distribution coefficient =( 5 × 1.1 × 10^-6 ) / 1.1 × 10^-6 + 3.2 × 10^-5 M. = 5.5 × 10^-6/ 3.2 = 0.00000171875

The fraction remaining from the compound = 45.0 mL / 45.0 mL + (0.00000171875 × 125).

= 0.999995.

Thus, the concentration at pH = 4.5 = 0.999995 × 0.0450 M = 0.045 M

(B). pH=6.50, thus the concentration of Hydrogen ion = 10^-6.5 = 3.2 × 10^-7 M.

distribution coefficient = (partition coefficient) × ka / ka + ( concentration of Hydrogen ion,H^+).

distribution coefficient = (5 × 1.1 × 10^-6)/ 1.1 × 10^-6 + 3.2 × 10^-7 M).

distribution coefficient = 5.5 × 10^-6/ 1.42 × 10^-6 = 3.9.

Therefore, the concentration = 3.9 × 0.0450 M = 0.175 M.

8 0
3 years ago
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