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The rate law equation for Ozone reaction
r=k[O][O₂]
<h3>Further explanation</h3>Given
Reaction of Ozone :.
O(g) + O2(g) → O3(g)
Required
the rate law equation
Solution
The rate law is a chemical equation that shows the relationship between reaction rate and the concentration / pressure of the reactants
For reaction
aA + bB ⇒ C + D
The rate law can be formulated:
where
r = reaction rate, M / s
k = constant, mol¹⁻⁽ᵃ⁺ᵇ⁾. L⁽ᵃ⁺ᵇ⁾⁻¹. S⁻¹
a = reaction order to A
b = reaction order to B
[A] = [B] = concentration of substances
So for Ozone reaction, the rate law (first orde for both O and O₂) :
12 atm is the new pressure of the air‑fuel mixture when A gaseous air‑fuel mixture in a sealed car engine cylinder has an initial volume of 600 ml at 1.0atm and final volume of 50 ml.
Explanation:
Data given:
The air fuel mixture is assumed to be having ideal behaviour
initial volume of gaseous air fuel mixture V1 = 600 ml
initial pressure of gaseous air fuel mixture P1= 1 atm
final volume when piston is removed, V2= 50 ml
final pressure of the gaseous air mixture, P2 = ?
Applying the Boyle's Law,
P1V1 = P2V2
rearranging the equation:
P2 =
putting the value in the equation,
P2 =
P2 = 12 atm
the pressure is increased to 12 atm when volume is reduced to 50 ml.