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RideAnS [48]
3 years ago
14

A solution has a pOH of 8.20. What is the concentration of H3O+?

Chemistry
1 answer:
Allisa [31]3 years ago
3 0

The correct answer is B. 1.6\times 10^{-6}

Explanation

The question provides us with information about the concentration of [OH^{-} ] and we are supposed to use this information to find the [H^{+} ] concentration. The pH of a solution gives us information about [H^{+} ]

If we the reaction is in equilibrium and with standard conditions of 25°C, then pH is given by the formula

14 = pH + pOH\\\implies pH= 14 - pOH= 14-8.20= 5.8.

Once we find the pH we use the relationship pH= -log[H^{+} ], then the [H^{+} ],is given by

pH = -log[H^{+} ]\\\implies [H^{+} ]= 10^{-pH} = 10^{-5.8}= 1.58 \times 10^{-6}

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The quantity of heat required to change the temperature of 1 g of a substance by 1°C is defined as ____.
Allushta [10]

Answer:

specific heat

Explanation:

please like,rate and tag as brainliest

5 0
3 years ago
Determine the number of HC=CH, monomeric units in one molecule of polyethylene with a molar
VladimirAG [237]

polyethylene contains HC=CH units.

mass of this is 26 gram/mol

number of such units =13500/26

3 0
3 years ago
How many moles of water are needed to react with 2.2 moles of li2o? given: li2o + h2o â 2 lioh?
Debora [2.8K]
Examining the given reaction:
Li2O + H2O ........> 2LiOH
we find that, 1 mole of Li2O is required to react with one mole of H2O in order to produce two moles of LiOH.

Therefore, the ration between the required Li2O and H2O is 1:1
Based on this, 2.2 moles of H2O (water) are required to react with 2.2 moles of Li2O
5 0
3 years ago
Using standard heats of formation, calculate the standard enthalpy change for the following reaction. 2NH3(g) 3N2O(g)4N2(g) 3H2O
trasher [3.6K]

Answer: \Delta H^{0} = -879.15 kJ/mol

Explanation: <u>Heats</u> <u>of</u> <u>formation</u> is the amount of heat necessary to create 1 mol of a compound from its molecular constituents. The basic conditions the substance is formed is at standard conditions: 1 atm and 25°C. Each compound has its own heat of formation per mol of compound (kJ/mol), but to an element is assigned a value of zero.

<u>Standard</u> <u>Enthalpy</u> <u>Change</u> is defined as the heat absorbed or released when a reaction takes place. It can be positive or negative, which means reaction is endothermic or exothermic, respectively.

Enthalpy change is calculated as the difference between the sum of heat formation of products and the sum of heat formation of the reactants:

\Delta H^{0}=\Sigma H^{0}_{f}_{(products)}-\Sigma H^{0}_{f}_{(reactants)}

For the reaction

   2NH₃   +      3N₂O   →      4N₂    +     3H₂O

2(-46.2)   +     3(82.05)      4(0)    +    3(-241.8)

\Delta H^{0}=3(-241.8)-[ 2(-46.2)+3(82.05)]

\Delta H^{0}=-725.4-153.75

\Delta H^{0}=-879.15

<u>The standard enthalpy change for the reaction is </u>\Delta H^{0}=-879.15<u> kJ</u>

8 0
2 years ago
How many atoms are there in 5K2CO3
Dvinal [7]

Answer:

Depends on what are you refering to

Explanation:

So depending on what you are looking for (your question is quite vauge)

there are 5 atoms of the comopound (K2CO3)

within that compound, there are 2 atoms of Potassium and 1 atom of Carbonate. Within Carbonate there are 4 atoms (1 carbon and 3 oxygens)

so answers may be

5, 15, or 25.

I hope this helps.

4 0
2 years ago
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