Answer:
Answer choice B
Step-by-step explanation:
The measures of angles on touching the opposite sides of the circles are always half the lengths of their respective arc. 126/2=63, or answer choice B. Hope this helps!
This question is Incomplete
Complete Question
Researchers recorded the speed of ants on trails in their natural environments. The ants studied, Leptogenys processionalis, all have the same body size in their adult phase, which made it easy to measure speeds in units of body lengths per second (bl/s). The researchers found that, when traffic is light and not congested, ant speeds vary roughly Normally, with mean 6.20 bl/s and standard deviation 1.58 bl/s. (a) What is the probability that an ant's speed in light traffic is faster than 5 bl/s? You may find Table B useful. (Enter your answer rounded to four decimal places.)
Answer:
0.7762
Step-by-step explanation:
We solve using z score formula
z = (x-μ)/σ, where
x is the raw score
μ is the population mean
σ is the population standard deviation.
Population mean = 6.20 bl/s
Standard deviation = 1.58 bl/s.
x = 5 bl/s
z = 5 - 6.20/1.58
z = -0.75949
The probability that an ant's speed in light traffic is faster than 5 bl/s is P( x > 5)
Probability value from Z-Table:
P(x<5) = 0.22378
P(x>5) = 1 - P(x<5)
= 1 - 22378
= 0.77622
Approximately to 4 decimal places = 0.7762
The probability that an ant's speed in light traffic is faster than 5 bl/s is 0.7762
<u>Answer:</u>
-348
<u>Step-by-step explanation:</u>
We are given the following arithmetic sequence and we are to find the sum of its first 12 terms:
1, -4, -9, -14, . . .
For that, we will use the formula for the sum of the arithmetic mean:

We know the value of the first term (
) but we need to find the value of
. So we will use the following formula:



Substituting these values in the sum formula to get:

-348
<h2>
Hello!</h2>
The answer is:
The equation of the line which includes the points (-5,5) and (2,5) is:

<h2>
Why?</h2>
To find the line which includes the points (-5,5) and (2,5) we can use the following equation:

So, using the points (-5,5) and (2,5), we have:





We have that the equation of the line which includes the points (-5,5) and (2,5) is:

Have a nice day!
Note: I have attached a picture for better understanding.