Ask question

Ask question

All categories

3 years ago

5

The Indian plate and the Eurasian plate collided to create the Himalayan mountains. Which

1 answer:

musickatia [10]3 years ago

3 0

Answer:

Greater acceleration of the plates towards each other

Explanation:

If more force is added to the convection currents, there would be a greater acceleration of the plates towards each other.

A lithospheric plate is driven by underlying asthenosphere which is ductile and readily flows. The plate lies on the asthenosphere.

The rate of movement of the asthenosphere determines the rate at which the plate above is moving.

The greater the convection below, the faster the plate moves.

You might be interested in

A capacitor is being charged from a battery and through a resistor of 10 kΩ. It is observed that the voltage on the capacitor ri

swat32

Answer:

$C = 2.48 \times 10^{-4} Farad$

Explanation:

As per the equation of voltage on capacitor we know that

$V = V_{max}(1 - e^{-\frac{t}{\tau}})$

now we know that voltage reached to its 80% of maximum value in 4 second time

so we will have

$0.80 V_{max} = V_{max}(1 - e^{-\frac{4}{\tau}})$

$0.20 = e^{-\frac{4}{\tau}}$

$-\frac{4}{\tau} = ln(0.20)$

$-\frac{4}{\tau} = -1.61$

$\tau = 2.48$

as we know that

$\tau = RC$

$(10 k ohm)(C) = 2.48$

$C = 2.48 \times 10^{-4} Farad$

4 0

3 years ago

Two massless bags contain identical bricks, each brick having a mass M. Initially, each bag contains four bricks, and the bags m

stepladder [879]

Answer: $F_{2}=\frac{3}{4}F_{1}$

Explanation:

According to Newton's law of universal gravitation:

$F=G\frac{m_{1}m_{2}}{r^2}$

Where:

$F$ is the module of the force exerted between both bodies

$G$ is the universal gravitation constant.

$m_{1}$ and $m_{2}$ are the masses of both bodies.

$r$ is the distance between both bodies

In this case we have two situations:

1) Two bags with masses $4M$ and $4M$ mutually exerting a gravitational attraction $F_{1}$ on each other:

$F_{1}=G\frac{(4M)(4M)}{r^2}$ (1)

$F_{1}=G\frac{16M^2}{r^2}$ (2)

$F_{1}=16\frac{GM^2}{r^2}$ (3)

2) Two bags with masses $2M$ and $6M$ mutually exerting a gravitational attraction $F_{2}$ on each other (assuming the distance between both bags is the same as situation 1):

$F_{2}=G\frac{(2M)(6M)}{r^2}$ (4)

$F_{2}=G\frac{12M^2}{r^2}$ (5)

$F_{2}=12\frac{GM^2}{r^2}$ (6)

Now, if we isolate $\frac{GM^2}{r^2}$ from (3):

$\frac{F_{1}}{16}=\frac{GM^2}{r^2}$ (7)

Substituting $\frac{GM^2}{r^2}$ found in (7) in (6):

$F_{2}=12(\frac{F_{1}}{16})$ (8)

$F_{2}=\frac{12}{16}F_{1}$ (9)

Simplifying, we finally get the expression for $F_{2}$ in terms of $F_{1}$ :

$F_{2}=\frac{3}{4}F_{1}$

5 0

4 years ago

The Earth can be approximated as a sphere of uniform density, rotating on its axis once a day. The mass of the Earth is 5.97×10^

ser-zykov [4K]

I had the same quiz… it’s a

8 0

3 years ago

A particle with charge -5 C initially moves at v = (1.00 i^ + 7.00 j^ ) m/s. If it encounters a magnetic field B =80 Tkˆ, find t

algol [13]

Answer:

The magnetic force is $\= F = 400\r j + 2800\r i$

Explanation:

From the question we are told that

The charge is $q = -5C$

The velocity is $v = (1.00\ \r i + 7.00 \ \r j )\ m/s$

The magnetic field is $B = 80 \r k \ \ T$

Generally the magnetic force is mathematically represented as

$\= F = q \= v \ \ X \ \ \= B$

=> $\= F = -5 (1.0 \r i + 7.0 \r j ) \ \ X \ \ 80 \r k$

=> $\= F = -5.0 \r i + 35\r j \ \ \ X \ \ 80\r k$

=> $\= F = 400\r j + 2800\r i$ N/B - Applied cross - product of unit vector

8 0

4 years ago

If the mass of an object increases, the force acting on it, such as gravitational force, also increases

strojnjashka [21]

Its true because I just took the the test and it was right
I hope i helped you got it right

4 0

4 years ago