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padilas [110]
3 years ago
5

The Indian plate and the Eurasian plate collided to create the Himalayan mountains. Which

Physics
1 answer:
musickatia [10]3 years ago
3 0

Answer:

Greater acceleration of the plates towards each other

Explanation:

If more force is added to the convection currents, there would be a greater acceleration of the plates towards each other.

 A lithospheric plate is driven by underlying asthenosphere which is ductile and readily flows. The plate lies on the asthenosphere.

The rate of movement of the asthenosphere determines the rate at which the plate above is moving.

The greater the convection below, the faster the plate moves.

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A capacitor is being charged from a battery and through a resistor of 10 kΩ. It is observed that the voltage on the capacitor ri
swat32

Answer:

C = 2.48 \times 10^{-4} Farad

Explanation:

As per the equation of voltage on capacitor we know that

V = V_{max}(1 - e^{-\frac{t}{\tau}})

now we know that voltage reached to its 80% of maximum value in 4 second time

so we will have

0.80 V_{max} = V_{max}(1 - e^{-\frac{4}{\tau}})

0.20 = e^{-\frac{4}{\tau}}

-\frac{4}{\tau} = ln(0.20)

-\frac{4}{\tau} = -1.61

\tau = 2.48

as we know that

\tau = RC

(10 k ohm)(C) = 2.48

C = 2.48 \times 10^{-4} Farad

4 0
3 years ago
Two massless bags contain identical bricks, each brick having a mass M. Initially, each bag contains four bricks, and the bags m
stepladder [879]

Answer: F_{2}=\frac{3}{4}F_{1}

Explanation:

According to Newton's law of universal gravitation:

F=G\frac{m_{1}m_{2}}{r^2}

Where:

F is the module of the force exerted between both bodies

G is the universal gravitation constant.

m_{1} and m_{2} are the masses of both bodies.

r is the distance between both bodies

In this case we have two situations:

1) Two bags with masses 4M and 4M mutually exerting a gravitational attraction F_{1} on each other:

F_{1}=G\frac{(4M)(4M)}{r^2}   (1)

F_{1}=G\frac{16M^2}{r^2}   (2)

F_{1}=16\frac{GM^2}{r^2}   (3)

2) Two bags with masses 2M and 6M mutually exerting a gravitational attraction F_{2} on each other (assuming the distance between both bags is the same as situation 1):

F_{2}=G\frac{(2M)(6M)}{r^2}   (4)

F_{2}=G\frac{12M^2}{r^2}   (5)

F_{2}=12\frac{GM^2}{r^2}   (6)

Now, if we isolate \frac{GM^2}{r^2} from (3):

\frac{F_{1}}{16}=\frac{GM^2}{r^2}   (7)

Substituting \frac{GM^2}{r^2}  found in (7) in (6):

F_{2}=12(\frac{F_{1}}{16})   (8)

F_{2}=\frac{12}{16}F_{1}   (9)

Simplifying, we finally get the expression for F_{2}  in terms of F_{1} :

F_{2}=\frac{3}{4}F_{1}  

5 0
4 years ago
The Earth can be approximated as a sphere of uniform density, rotating on its axis once a day. The mass of the Earth is 5.97×10^
ser-zykov [4K]
I had the same quiz… it’s a
8 0
3 years ago
A particle with charge -5 C initially moves at v = (1.00 i^ + 7.00 j^ ) m/s. If it encounters a magnetic field B =80 Tkˆ, find t
algol [13]

Answer:

The magnetic force is  \= F  =  400\r j + 2800\r i

Explanation:

From the question we are  told that

  The  charge is  q =  -5C

  The  velocity is  v  =  (1.00\ \r i +  7.00 \ \r j )\ m/s

   The  magnetic field is  B =  80 \r k \ \ T

Generally the magnetic force is mathematically represented as

        \=  F =  q  \= v  \  \  X \ \ \= B

=>     \=  F = -5  (1.0 \r i  + 7.0 \r j  ) \  \  X \ \  80 \r k

=>    \= F  =  -5.0 \r i +  35\r j  \ \ \ X \ \ 80\r k

=>  \= F  =  400\r j + 2800\r i    N/B - Applied cross - product of unit vector

8 0
4 years ago
If the mass of an object increases, the force acting on it, such as gravitational force, also increases
strojnjashka [21]
Its true because I just took the the test and it was right
I hope i helped you got it right
4 0
4 years ago
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