Answer:
a) 72.54° and It will take the woman 33.4m
Explanation:
The woman runs with a constant speed V1 = 6m/s
V2 = 20m/s
V1 = V2 cos θ
Cos θ= V1/V2= 6/20
Cos θ= 0.3
Cos^-1 0.3=72.54°
Using Range formular for projectile
R= (V2 Cos θ)/g (V2 Sin θ)^2 +sqrt(V2 Sin θ)^2 + 2gh)
R= (20cos72.54)(2Sin72.54+sqrt(20Sin72.54)^2 + 2×9.8×45
R=33.4m
b )
see the attached file
Answer:
Compression in the spring, x = 0.20 m
Explanation:
Given that,
Spring constant of the spring, k = 490 N/m
Mass of the block, m = 5 kg
To find,
Compression in the spring.
Solution,
Since the block is suddenly dropped on the spring gravitational potential energy of block converts into elastic potential energy of spring. Its expression is given by :
Where
x is the compression in the spring
x = 0.20 m
So, the compression in the spring due to block is 0.20 meters.