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2 years ago

What does newton's first law describes

1 answer:

5 0

Earlier, we stated Newton's first law as “A body at rest remains at rest or, if in motion, remains in motion at constant velocity unless acted on by a net external force.” It can also be stated as “Every body remains in its state of uniform motion in a straight line unless it is compelled to change that state by forces
For example-A stationary object with no outside force will not move. With no outside forces, a moving object will not stop. An astronaut who has their screwdriver knocked into space will see the screwdriver continue on at the same speed and direction forever.

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Find the acceleration of a car that can go from rest to 50 km/h in 13 s

ziro4ka [17]

The acceleration of the car is 1.067 m/ $s^{2}$ .

<u>Explanation:</u>

Acceleration is the measure of change in velocity experienced by any object for a given time period. So it is determined as the ratio of difference in the velocity to the time period.

As here the initial velocity is stated as zero, so u = 0. And the final velocity is termed as 50 km/h. Then we have to determine the acceleration in 13 s. So here we have to convert the units as common units. Thus, 50 km/h should be converted to m/s as $\frac{50*1000}{3600}=13.88 m/s$

So now, the initial velocity u = 0 and final velocity v = 13.88 m/s and the time period is given as t = 13 s.

$Acceleration = \frac{v-u}{t}=\frac{13.88-0}{13}=1.067 m/s^{2}$

So the acceleration of the car is 1.067 m/ $s^{2}$ .

8 0

3 years ago

A dog pulls on a leash with a force of 15 23 is a big dog. The leash makes an angle of 36.7 degrees to the horizontal. What are

ch4aika [34]

Answer:

$x = 12.027N$ and $y = 8.964N$

Explanation:

The first sentence of this question is not explanatory enough. However, I'll assume the force to be 15N

$Force = 15N$

$\theta = 36.7$ to the horizontal

Required

Solve for the x and y components

Since the given angle is to the horizontal, the x and y coordinates are calculated using the following illustrations.

$Sin\theta = \frac{y}{Force}$ ---- y component

$Cos\theta = \frac{x}{Force}$ ---- x component

Calculating the y component.

Substitute 15 for Force and 36.7 for $\theta$

$Sin\theta = \frac{y}{Force}$ becomes

$Sin(36.7) = \frac{y}{15}$

Make y the subject

$y = 15 * Sin(36.7)$

$y = 15 * 0.5976$

$y = 8.964N$

Calculating the x component.

Substitute 15 for Force and 36.7 for $\theta$

$Cos\theta = \frac{x}{Force}$ becomes

$Cos(36.7) = \frac{x}{15}$

Make y the subject

$x = 15 * Cos(36.7)$

$x = 15 * 0.8018$

$x = 12.027N$

<em>Hence, the x and y components of the force are: 8.964N and 12.027N respectively.</em>

6 0

2 years ago

I need a walk through please

babymother [125]

Answer:

11,100 N

Explanation:

Draw the car on the incline. Label the weight and normal forces. Call the direction normal to the incline y, and the direction parallel to the incline x.

If it helps, rotate the incline so that the surface of the incline is flat.

Use trigonometry to determine the components of the weight force. The y component of the weight is:

Wᵧ = mg cos θ

Wᵧ = (1150 kg) (9.8 m/s²) (cos 8.70°)

Wᵧ = 11,100 N

7 0

1 year ago

Two particles of a gas collide. Why is this considered an elastic collision? (1 point)

dezoksy [38]

I don’t know really really I don’t know

7 0

2 years ago

Read 2 more answers

It's nighttime, and you've dropped your goggles into a 3.2-mm-deep swimming pool. If you hold a laser pointer 1.1 mm above the e

Savatey [412]

Answer: 5.30m

Explanation:

depth of pool = 3.2 m

i = 67.75°

Using snell's law, we have,

n₁ × sin(i) = n₂ × 2 × sin(r)

n₁ = 1, n₂ =1.33, r= 44.09°

Hence,

Distance of Google from edge if pool is:

2.2 + d×tan(r) = 2.2 + (3.2 × tan(44.09°) =5.30m

5 0

3 years ago

What does newton's first law describes​

What does newton's first law describes