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2 years ago

A student flips a coin 100 times. The coin lands on heads 52 times.

Mathematics

1 answer:

nata0808 [166]2 years ago

7 0

The experimental probability of landing on heads is the same as the theoretical probability of landing on heads.

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I wasn’t at school when we learned this. Could someone he

Ksenya-84 [330]

Answer:

a= (1,4)

b=(4,2)

c=(2,6)

d=(2,-1)

Step-by-step explanation:

All I did was looked at the regions the points began and ended. I'm not 100% this is correct but I hope I helped!

6 0

2 years ago

A balloon holds 5.2 cubic feet of air. The balloon is blown up larger to hold 8.3 cubic feet of air. What is the percent

Eddi Din [679]

Answer:

8.3+5.2

Step-by-step explanation:

5 0

2 years ago

Find y when x= -3 for y=2/3 x

marusya05 [52]

Answer:

y = - 2

Step-by-step explanation:

$y = \frac{2}{3} x \\ \\ plug \: x = - 3 \\ \\ y = \frac{2}{ \cancel3} \times ( \cancel{ - 3}) \: \: \red{ \bold{- 1}}\\ \\ y = 2( - 1) \\ \\ y = - 2$

7 0

2 years ago

Solve the differential. This was in the 2016 VCE Specialist Maths Paper 1 and i'm a bit stuck

Nimfa-mama [501]

$\sqrt{2 - x^{2}} \cdot \frac{dy}{dx} = \frac{1}{2 - y}$
$\frac{dy}{dx} = \frac{1}{(2 - y)\sqrt{2 - x^{2}}}$

Now, isolate the variables, so you can integrate.
$(2 - y)dy = \frac{dx}{\sqrt{2 - x^{2}}}$
$\int (2 - y)\,dy = \int\frac{dx}{\sqrt{2 - x^{2}}}$
$2y - \frac{y^{2}}{2} = sin^{-1}\frac{x}{\sqrt{2}} + \frac{1}{2}C$

$4y - y^{2} = 2sin^{-1}\frac{x}{\sqrt{2}} + C$
$y^{2} - 4y = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} - 4 = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} = 4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C$

$y - 2 = \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$
$y = 2 \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$

At x = 1, y = 0.
$0 = 2 \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$
$-2 = \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C > 0$
$\therefore 2 = \sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 = 4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C$
$0 = -2sin^{-1}\frac{1}{\sqrt{2}} - C$
$C = -2sin^{-1}\frac{1}{\sqrt{2}} = -2\frac{\pi}{4}$
$C = -\frac{\pi}{2}$

$\therefore y = 2 - \sqrt{4 + \frac{\pi}{2} - 2sin^{-1}\frac{x}{\sqrt{2}}}$

6 0

3 years ago

Help please need answer asap

MaRussiya [10]

Answer:

f(x) = x - 3

Step-by-step explanation:

y = mx + b

first let's find b, the y-intercept

based on the graph, the y-intercept is (0,-3), so b = -3

immediately, we can eliminate f(x) = 3 - x and f(x) = -3x

comment any questions pls

6 0

3 years ago

Read 2 more answers