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vlabodo [156]
3 years ago
11

In ΔUVW, \overline{UW} UW is extended through point W to point X, \text{m}\angle UVW = (3x+16)^{\circ}m∠UVW=(3x+16) , \text{m}\a

ngle WUV = (2x+8)^{\circ}m∠WUV=(2x+8) and \text{m}\angle VWX = (8x-18)^{\circ}m∠VWX=(8x−18) Find \text{m}\angle WUV.m∠WUV.
Mathematics
2 answers:
wel3 years ago
6 0
The value of x is 9°
Step-by-step explanation:
The given parameters are;
ΔUVW with side UW extended to X
m∠UVW = (3x + 4)°
m∠VWX = (8x -12)°
m∠WUV = (x + 20)°
We have that m∠UVW + m∠WUV + m∠VWU = 180° (Sum of the interior angles of a triangle theorem)
∴ m∠VWU = 180° - (m∠UVW + m∠WUV)
Also we have that m∠VWX and m∠VWU are supplementary angles, (The sum of angles on a straight line)
∴ m∠VWX + m∠VWU = 180° (Definition of supplementary angles)
m∠VWU = 180° - m∠VWX
∴ m∠VWX = (m∠UVW + m∠WUV)
Substituting the values, gives;
(8x -12)° = (3x + 4)° + (x + 20)°
8x - 3x - x = 4 + 20 + 12
4x = 36
x = 36/4 = 9
x = 9°.

statuscvo [17]3 years ago
4 0

Answer:

36

Step-by-step explanation:

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1/2(4x-2)-2/3(6x+9) greater or equal to 4
Simora [160]
1/2(4x-2)-2/3(6x+9)
(2x-1)-(4x+6)
2x-1-4x+62x-4x-1+6
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So I believe that it is greater than 4
8 0
3 years ago
PLEASE ASAP ILL GIVE YOU BRAINLIEST
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1. The average yards gained per play was 10.56
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7 0
2 years ago
4,275.50= 391/2 of ____
murzikaleks [220]

Answer:

The required value for the blank is 21.8696

Step-by-step explanation:

Consider the provided information,

4,275.50= 391/2 of ____

Replace blank with x.

4,275.50 = 391/2 of x

Use sign of multiplication for "of".

4,275.50 = \frac{391}{2} \times x

Solve the above expression for x.

x=\frac{4,275.50\times 2}{391}

x=21.8696

Thus, the required value for the blank is 21.8696

8 0
3 years ago
Prove for any positive integer n, n^3 +11n is a multiple of 6
suter [353]

There are probably other ways to approach this, but I'll focus on a proof by induction.

The base case is that n = 1. Plugging this into the expression gets us

n^3+11n = 1^3+11(1) = 1+11 = 12

which is a multiple of 6. So that takes care of the base case.

----------------------------------

Now for the inductive step, which is often a tricky thing to grasp if you're not used to it. I recommend keeping at practice to get better familiar with these types of proofs.

The idea is this: assume that k^3+11k is a multiple of 6 for some integer k > 1

Based on that assumption, we need to prove that (k+1)^3+11(k+1) is also a multiple of 6. Note how I've replaced every k with k+1. This is the next value up after k.

If we can show that the (k+1)th case works, based on the assumption, then we've effectively wrapped up the inductive proof. Think of it like a chain of dominoes. One knocks over the other to take care of every case (aka every positive integer n)

-----------------------------------

Let's do a bit of algebra to say

(k+1)^3+11(k+1)

(k^3+3k^2+3k+1) + 11(k+1)

k^3+3k^2+3k+1+11k+11

(k^3+11k) + (3k^2+3k+12)

(k^3+11k) + 3(k^2+k+4)

At this point, we have the k^3+11k as the first group while we have 3(k^2+k+4) as the second group. We already know that k^3+11k is a multiple of 6, so we don't need to worry about it. We just need to show that 3(k^2+k+4) is also a multiple of 6. This means we need to show k^2+k+4 is a multiple of 2, i.e. it's even.

------------------------------------

If k is even, then k = 2m for some integer m

That means k^2+k+4 = (2m)^2+(2m)+4 = 4m^2+2m+4 = 2(m^2+m+2)

We can see that if k is even, then k^2+k+4 is also even.

If k is odd, then k = 2m+1 and

k^2+k+4 = (2m+1)^2+(2m+1)+4 = 4m^2+4m+1+2m+1+4 = 2(2m^2+3m+3)

That shows k^2+k+4 is even when k is odd.

-------------------------------------

In short, the last section shows that k^2+k+4 is always even for any integer

That then points to 3(k^2+k+4) being a multiple of 6

Which then further points to (k^3+11k) + 3(k^2+k+4) being a multiple of 6

It's a lot of work, but we've shown that (k+1)^3+11(k+1) is a multiple of 6 based on the assumption that k^3+11k is a multiple of 6.

This concludes the inductive step and overall the proof is done by this point.

6 0
3 years ago
Read 2 more answers
*Click the photo*
Charra [1.4K]

Answer:

137.5 Miles

Step-by-step explanation:

2 = 50 Right? So if you were to divide 50 by 2, you would get 1 = 25. All you would have to do from there would be to multiply 25 times 5.5 to get 137.5.

8 0
3 years ago
Read 2 more answers
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