If A is a 3×3 singular matrix such that λ1=1−i is an eigenvalue of A, then the other eigenvalues of A are 0,1+i
1 answer:
Answer:
1 + i
Step-by-step explanation:
Given that A is a 3 * 3 singular matrix
one of its eigenvalue ( λ1 ) = 1 - i
Given that the determinant of a singular matrix is = 0
therefore the second eigen value ( λ2 ) = 1 + i
1 - i + 1 + i = 0
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