Which phrase best completes the diagram thingy

Which is the basic functional unit of life?

lord [1]

Answer:

It’s the cell

6 0

2 years ago

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Proteins are three dimensional molecules made of strands of amino acids (imagine a ball of string). There are 20 different amino

zlopas [31]

Answer:

A series of nonpolar amino acids would most likely be located in the interior region of the tridimensional molecule.

Explanation:

Proteins are formed by linearly arranged amino acids, each with a side chain: the R-group.

Of the 20 different amino acids that compose the proteins, about half of them -10- are non-polar. Their R-groups are not stable if they are in contact with water, meaning that non-polar amino acids are hydrophobic.

When proteins are synthesized, they acquire a three-dimensional structure that makes them more stable. Lineal polypeptides get folded and turn into a shape that makes them more stable in the environment and capable of accomplishing their biological role. When they are in an aqueous media, their bent shape leaves the hydrophilic R-groups in contact with water. The hydrophilic R-groups stick in the center of the polypeptide, facing the protein interior, and avoiding interaction with water.

3 0

3 years ago

62 Which law of motion accounts for the following statement? "When a marble

svp [43]

Answer:

the answer is Newton's third and Second law

Explanation:

Newton's second law tells us that the force that is generated on a body is proportional to the acceleration it acquires.

F= M*A

at lower mass greater acceleration

Newton's third law explains that for each force that acts on a body, it performs a force of equal intensity and direction but in the opposite direction to the body than gender.

I hope it's help you

4 0

3 years ago

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If scientists want to solve an environmental problem they are most likely to use ?

antiseptic1488 [7]

Answer:

Technology

Explanation:

5 0

3 years ago

2. Dominant trait: cleft chin (C) Mother’s gametes: Cc

andre [41]

.2. Offspring Genotypes will be Cc or cc.

Offspring phenotypes : Cleft chin or no cleft chin.

% chance child will have cleft chin: 50%

3. % chance child will have arched feet: 25%

4. % chance child will have blonde hair: 50%

5. % chance child will have normal vision: 25%

Explanation:

CASE 1 :

Dominant trait: cleft chin (C)

Recessive trait: lacks cleft chin (c)

Father’s gametes: cc

Mother’s gametes: Cc

There are two possible combination of Gametes ,

C fom mother and c from father= Cc

c from mother and c from father = cc

Gametes of Cc Parents= $\frac{1}{2}C + \frac{1}{2} c$ ........(i)

Gametes of cc parents = $\frac{1}{2}c + \frac{1}{2}c$ .........(ii)

Combining (i) and (ii) we get,

$\frac{1}{2} Cc + \frac{1}{2} cc$

There fore offspring Genotypes will be Cc or cc

Offspring phenotypes :

Genotype Cc then phenotype= Cleft chin

Genotype cc then phenotype = Lacks cleft chin.

percentage chance child will have cleft chin = $\frac{0.5}{1}$ ×100

Therefore the chance is 50%.

CASE 2 :

Dominant trait: flat feet (A)

Recessive trait: arched feet (a)

Mother’s gametes: Heterozygous (Aa)

Father’s gametes: Heterozygous (Aa)

There are four possible combination of genotypes are =AA , Aa, Aa and aa

i.e. A from mother, A from father= AA

A from mother, a from father =Aa

a from mother, A from Father = Aa

a from mother, a from father = aa

Gametes of Aa parent = $\frac{1}{2} A + \frac{1}{2} a$

Gametes of other Aa parent = $\frac{1}{2} A + \frac{1}{2} a$

..................................................................................

$\frac{1}{4} AA + \frac{1}{4} Aa$

+ $\frac{1}{4} Aa$ + $\frac{1}{4} aa$

..........................................................................................

$\frac{1}{4}AA + \frac{1}{2}Aa +\frac{1}{4} aa$

Offspring Genotypes will be: AA or Aa or aa

Offsprings phenotype will be:

Genotype AA then phenotype will be Flat feet

Genotype Aa then phenotype will be flat feet

Genotype aa then Phenotype will be arched feet.

Percentage chance child will have arched feet = $\frac{0.25}{1}$ × 100 = 25%

CASE 3:

Dominant trait: Brown hair (B)

Recessive trait: Blonde hair (b)

Mother’s gametes: Homozygous recessive (bb)

Father’s gametes: Heterozygous (Bb)

This case is very similar to the case 1 as one parent is homozygous recessive and other parent is heterozygous.

Resulting in half Bb and halve bb combination.

Genotypes will be Bb or bb

Phenotypes will be :

Genotype Bb then phenotype Brown hair

Phenotype bb then Phenotype bb.

% chance child will have blonde hair: 50%

CASE 4:

Dominant trait: farsightedness (F)

Recessive trait: normal vision (f)

Mother’s gametes: Heterozygous (Ff)

Father’s gametes: Heterozygous (Ff)

This Case is similar to case 2

it will result in one-fourth FF , half Ff and one-fouth ff combination.

Therefore Genotypes will be: FF, Ff and ff

Phenotypes:

Genotype FF then phenotype farsightedness

Genotype Ff then phenotype farsightedness

Genotype ff then phenotype normal vision.

% chance child will have normal vision: 25%

3 0

3 years ago