Answer:
1 mile/hour is equivalent to 1.47 feet/seconds
Step-by-step explanation:
Given
Required
Determine the equivalent of 1 mile/hour
Express 60 as 60 * 1
Divide both sides by 60
Reorder
Divide 88 by 60
Approximate to 3 significant figures
Hence;
1 mile/hour is equivalent to 1.47 feet/seconds
Answer:
See explanation below
Step-by-step explanation:
BD - diagonal Added Construction
m∠CBD = m∠ADB Alternate Interior Angles Theorem
BD ≅ DB Reflexive Property
m∠A = m∠C Opposite ∠'s Congruent Theorem
ΔABD ≅ ΔCDB AAS or SAS
BC ≅ DA CPCTC
AC - diagonal Added Construction
m∠BCA = m∠CAD Alternate Interior Angles Theorem
AC ≅ CA Reflexive Property
m∠B = m∠D Opposite ∠'s Congruent Theorem
ΔABC ≅ ΔCDA AAS or SAS
AB ≅ CD CPCTC
This question has this set of answer choices:
a) when the plane cuts three faces of the cube, separating one corner from the others
b) when the plane passes through a pair of vertices that do not share a common face
c) when the plane is perpendicular to the base and intersects two adjacent vertical faces
d) when the plane makes an acute angle to the base and intersects three vertical faces
e) not enough information to answer the question
The right answer is the first choice: a) when the plane cuts three faces of the cube, separating one corner from the others
You can see a picture of this case in the figure attached: as you can see the cross section (in pink) is a triangle.
Answer:
b i think
Step-by-step explanation:
Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)
If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.
On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.
For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.
Then the range of F(x) is the interval [-π, π].
