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3 years ago

What will the answers for a ,b and c be

Physics

1 answer:

miss Akunina [59]3 years ago

3 0

Answer:

A. 1.6 Hz

B. 1000 m/s²

C. 50000 N

Explanation:

A. Determination of the frequency.

Period (T) = 0.625 s

Frequency (f) =?

f = 1/T

f = 1/0.625

f = 1.6 Hz

B. Determination of the acceleration.

Radius (r) = 10 m

Velocity (v) = 100 m/s

Acceleration (a) =?

a = v²/r

a = 100² / 10

a = 10000 / 10

a = 1000 m/s²

C. Determination of the net force.

Mass (m) = 50 Kg

Acceleration (a) = 1000 m/s²

Net force (F) =?

F = ma

F = 50 × 1000

F = 50000 N

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AURORKA [14]

Answer:

The answer would be the last option (the one with the arrow pointing sideways)

Explanation:

The arrow lost it's acceleration and is starting to go downwards but it isn't a straight slope down

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3 years ago

a 202 kg bumper car moving right at 8.50 m/s collides with a 355 kg car at rest. Find the total momentum of the system.

Hunter-Best [27]

Explanation:It is given that,

Mass of bumper car, m₁ = 202 kg

Initial speed of the bumper car, u₁ = 8.5 m/s

Mass of the other car, m₂ = 355 kg

Initial velocity of the other car is 0 as it at rest, u₂ = 0

Final velocity of the other car after collision, v₂ = 5.8 m/s

Let p₁ is momentum of of 202 kg car, p₁ = m₁v₁

Using the conservation of linear momentum as :

p₁ = m₁v₁ = -342 kg-m/s

So, the momentum of the 202 kg car afterwards is 342 kg-m/s. Hence, this is the required solution.

3 0

3 years ago

Read 2 more answers

A 33.0-kg child starting from rest slides down a water slide with a vertical height of 15.0 m. (Neglect friction.)

Temka [501]

This question involves the concept of the conservation of energy.

(a) The child's speed halfway will be "12.13 m/s".

(b) The child's speed three-fourth way will be "14.86 m/s".

(a)

Using the law of conservation of energy:

Potential Energy Lost = Kinetic Energy Gained

$mgh = \frac{1}{2}mv^2\\\\2gh = v^2\\\\v = \sqrt{2gh}$

where,

v = speed = ?

g = acceleration due to gravity = 9.81 m/s²

h = height lost = halfway = height/2 = 15 m/2 = 7.5 m

Therefore,

$v = \sqrt{(2)(9.81\ m/s^2)(7.5\ m)}$

v = 12.13 m/s

(b)

Using the law of conservation of energy:

Potential Energy Lost = Kinetic Energy Gained

$mgh = \frac{1}{2}mv^2\\\\2gh = v^2\\\\v = \sqrt{2gh}$

where,

v = speed = ?

g = acceleration due to gravity = 9.81 m/s²

h = height lost = three-fourth way down = $\frac{3}{4}height = \frac{3}{4}(15\ m) = 11.25\ m$

Therefore,

$v = \sqrt{(2)(9.81\ m/s^2)(11.25\ m)}$

v = 14.86 m/s

Learn more about the law of conservation of energy here:

brainly.com/question/20971995?referrer=searchResults

The attached picture shows the law of conservation of energy.

7 0

3 years ago

hey guys, l need some help! what is the weight of potatoes of mass 75 kg on the surface of the earth? (g=9.8m/s square) ans=735N

Airida [17]

Answer:

735N

Explanation:

Weight is a measurement of force.

F = Force

m = mass

a = acceleration

F = m*a

F = 75kg*9.8m/s²

F = 735N

8 0

3 years ago

One simple model for a person running the 100 m dash is to assume the sprinter runs with constant acceleration until reaching to

yaroslaw [1]

Complete Question:

One simple model for a person running the 100 m dash is to assume the sprinter runs with constant acceleration until reaching top speed, then maintains that speed through the finish line. If a sprinter reaches his top speed of 11.5 m/s in 2.24 s, what will be his total time?

Answer:

total time = 6.24 s

Explanation:

Using the equation of motion:

v = u + at

initial speed, u = 0 m/s

v = 11.5 m/s

t = 2.24 s

11.5 = 0 + 2.24a

a = 11.5/2.24

a = 5.13 m/s²

For the total time spent by the sprinter:

s = ut + 0.5at²

100 = 0.5 * 5.13 * t²

t² = 100/2.567

t² = 38.957

t = √38.957

t = 6.24 s

3 0

4 years ago