The answer is:
Fill in the blanks to complete the sentence.
Light acts like a PARTICAL when it bounces off surfaces,
and acts like a WAVE when it bends around objects.
I hope this helps you :>
Explanation:
As the given spheres are connected by a thin wire so, the potential on the spheres are the same.
......... (1)
Hence, total charge will be as follows.
= Q = -95.5 nC .......... (2)
Using the above two equations, the final equation will be as follows.
![q_{2} = \frac{Qr_{2}}{r_{1} + r_{2}}](https://tex.z-dn.net/?f=q_%7B2%7D%20%3D%20%5Cfrac%7BQr_%7B2%7D%7D%7Br_%7B1%7D%20%2B%20r_%7B2%7D%7D)
and, ![q_{1} = \frac{Qr_{1}}{r_{1} + r_{2}}](https://tex.z-dn.net/?f=q_%7B1%7D%20%3D%20%5Cfrac%7BQr_%7B1%7D%7D%7Br_%7B1%7D%20%2B%20r_%7B2%7D%7D)
Hence, we will calculate the charge on sphere B after the equilibrium is reached as follows.
![q_{2} = \frac{Qr_{2}}{r_{1} + r_{2}}](https://tex.z-dn.net/?f=q_%7B2%7D%20%3D%20%5Cfrac%7BQr_%7B2%7D%7D%7Br_%7B1%7D%20%2B%20r_%7B2%7D%7D)
= ![\frac{-95.5 \times 74.4 cm}{(11.5 + 74.4) cm}](https://tex.z-dn.net/?f=%5Cfrac%7B-95.5%20%5Ctimes%2074.4%20cm%7D%7B%2811.5%20%2B%2074.4%29%20cm%7D)
= 82.714 nC
Thus, we can conclude that the charge on sphere B after equilibrium has been reached is 82.714 nC.
D. 980, this is the best answer because 35 x 7 is 980 :)
Sunspots are spot like structure on the surface of sun, they are created due to geomagnetic flux which inhibits the convection of heat waves thus reducing the temperature of spot with some factor
Answer:
we got time and velocity over time.
so the distance is again the area underneath the graph
for a triangle with known base and height it's
4*10 / 2
distance traveled is 20
deceleration occurs when velocity decreases. that happens from t=2 till t=4
in 2 time-units we loose 10 units of velocity, so we decelerate by 5 units per 1 time
a (from t=2 to t=4) = -5v/t