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Anni [7]
1 year ago
5

What is nuclear power

Physics
1 answer:
katrin2010 [14]1 year ago
3 0

Answer:

<h2><em><u>D. All of the statements describe nuclear power</u></em></h2>

What is <em><u>NUCLEAR</u></em><em><u> </u></em><em><u>POWER</u></em><em><u>?</u></em><em><u> </u></em>

➡️ is the <u>use of nuclear</u> <u>reactions</u> to <u>produce electricity</u>.

➡️ it can be <u>obtained from nuclear</u> <u>fission, nuclear decay and nuclear fusion reactions. </u>

Hope it helps

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A cat’s crinkle ball toy of mass 15g is thrown straight up with an initial speed of 3m/s . Assume in this problem that air drag
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Answer:

(a)0.0675  J

(b)0.0675 J

(c)0.0675 J

(d)0.0675 J

(e)-0.0675 J

(f)0.459 m

Explanation:

15g = 0.015 kg

(a) Kinetic energy as it leaves the hand

E_k = \frac{mv^2}{2} = \frac{0.015*3^2}{2} = 0.0675  J

(b) By the law of energy conservation, the work done by gravitational energy as it rises to its peak is the same as the kinetic energy as the ball leave the hand, which is 0.0675 J

(c) The change in potential energy would also be the same as 0.0675J in accordance with conservation law of energy.

(d) The gravitational energy at peak point would also be the same as 0.0675J

(e) In this case as the reference point is reversed, we would have to negate the original potential energy. So the potential energy as the ball leaves hand is -0.0675J

(f) Since at the maximum height the ball has potential energy of 0.0675J. This means:

mgh = 0.0675

0.015*9.81h = 0.0675

h = 0.459 m

The ball would reach a maximum height of 0.459 m

4 0
3 years ago
Nine steps for developing scientific principles are
xxTIMURxx [149]

Answer:

1)Observe a phenomenon

2)Ask a question/ start inferring

3)Form a hypothesis

4)Create an experiment

5)Collect data

6)Compare results

7)Analyze

8)Report findings

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2 years ago
A speed skater moving across frictionless ice at 9.2 m/s hits a 5.0 m wide patch of rough ice. She slows steadily, then continue
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Answer:

a = -5.10 m/s^2

her acceleration on the rough ice is -5.10 m/s^2

Explanation:

The distance travelled on the rough ice is equal to the width of the rough ice.

distance d = 5.0 m

Initial speed u = 9.2 m/s

Final speed v = 5.8 m/s

The time taken to move through the rough ice can be calculated using the equation of motion;

d = 0.5(u+v)t

time t = 2d/(u+v)

Substituting the given values;

t = 2(5)/(9.2+5.8)

t = 2/3 = 0.66667 second

The acceleration is the change in velocity per unit time;

acceleration a = ∆v/t

a = (v-u)/t

Substituting the values;

a = (5.8-9.2)/0.66667

a = -5.099974500127

a = -5.10 m/s^2

her acceleration on the rough ice is -5.10 m/s^2

7 0
3 years ago
If you were a pastor, and you were getting married, would you hire a pastor, or would you do the wedding yourself?
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I would hire a pastor.
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3 years ago
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Answer:

Rubber is an insulator.

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2 years ago
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