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Aneli [31]
3 years ago
15

A carton of 12 rechargable batteries contains one that is defective. In how many ways can the inspector choose 3 of the batterie

s and (a) get the one that is defective, (b)not get the one that is defective?
Physics
1 answer:
atroni [7]3 years ago
6 0
There are 2 defective batteries and 10 good batteries. 
a) none of the defective batteries (10C3) = 120 
b) one of the defective batteries (10C2)(2C1) = 90 
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Properties that change when the size of an object changes are called?
frozen [14]
<span>A physical change involves a change in physical properties. Examples of physical properties include melting, transition to a gas, change ofstrength, change of durability, changes to crystal form, textural change, shape, size, color, volume and density.b

A) physical properties</span>
5 0
4 years ago
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You and a friend each drive 50.0 km. You travel at 90.0 km/h; your friend travels at 95.0 km/h. How long will your friend have t
netineya [11]

Answer:

1.08 hours

Explanation:

Distance = speed × time

Time = distance / speed

The time you spend driving is:

t = 50.0 km / (90.0 km/hr)

t = 0.555 hr

The time your friend spends driving is:

t = 50.0 km / (95.0 km/hr)

t = 0.526 hr

The total time is 0.555 hr + 0.526 hr = 1.08 hr.

5 0
3 years ago
Your racquetball opponent has poor reaction time and agility. A good offensive strategy would be to serve: (2 points) Group of a
spin [16.1K]

Answer:

b

Explanation:

6 0
3 years ago
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A gas within a piston–cylinder assembly undergoes a
IrinaVladis [17]

Answer:

W_{net}= -280.5 kJ

Q_{23}= 80.0 kJ

Explanation:

The net work of the cycle is the sum of works in each process.

<u>For the first process 1-2: </u> Let's apply the work definition.

W=\int pdV (1)

Now, we need the pressure. We know that pV=C, where C is a constant. Then  p_{1}V_{1}=10^{5}2=2*10^{5} [J]

So p=\frac{2*10^{5}}{V}

Let's put p in (1):

W_{12}=\int \frac{2*10^{5}}{V}dV=2*10^{5}\int \frac{1}{V}dV

W_{12}=2*10^{5}(ln(V_{2})-ln(V_{1}))=2*10^{5}(ln(0.2)-ln(2))=-460.5 kJ

Using the first law of thermodynamics we can find Q.

Q_{12}-W=\Delta U

Q_{12}=W+\Delta U=-460.5 + 100= -360.5 kJ

<u>Second process 2-3</u>

In this case, we have a constant volume, so the work done here is 0.

W_{23}=0

<u>Third process 3-1</u>

W_{31}=\int pdV=p\int dV=p(V_{2}-V_{1})

W_{31}=10^{5}(2-0.2)=180 kJ

Finally, the net work is:

W_{net}=W_{12}+W_{23}+W_{31}= -280.5 kJ

By the conservation of energy:

(Q_{12}+Q_{23}+Q_{31})-(W_{net})=\Delta E=0

Because there is no change in total energy.

So:

Q_{23}=W_{net}-Q_{12}= 80.0 kJ

It is a refrigerator because the net work is negative, it means it consumes energy.

I hope it helps you!

3 0
4 years ago
While looking at bromine (Br) on the periodic table, a student needs to find another element with very similar chemical properti
expeople1 [14]

Answer:

While looking at bromine (Br) on the periodic table, a student needs to find another element with very similar chemical properties but with a different atomic mass. Which best describes the student’s options?

i need the answer now

Explanation:

There are many possible elements, and they are all in the same vertical column as bromine.

5 0
3 years ago
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