The solution to the system of equation are x=2, y=0, z=6
<h3>System of equations</h3>
System of equations are equations that contains unknown variables.
Given the equations
3x+y+2z=8
8y+6z=36
12y+2z=12
From equation 2 and 3
8y+6z=36 * 1
12y+2z=12 * 3
______________
8y+6z=36
36y+6z= 36
Subtract
8y - 36y = 36 - 36
-28y =0
y = 0
Substitute y = 0 into equation 2
8(0)+6z=36
6z = 36
z = 6
From equation 1
3x+y+2z =8
3x + 0 + 2(6) = 8
3x = 8 - 12
3x = 6
x = 2
Hence the solution to the system of equation are x=2, y=0, z=6
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Answer:
Step-by-step explanation:
Firstly, note that -2i really is just z = 0 + (-2)i, so we see that Re(z) = 0 and Im(z) = -2.
When we're going from Cartesian to polar coordinates, we need to be aware of a few things! With Cartesian coordinates, we are dealing explicitly with x = blah and y = blah. With polar coordinates, we are looking at the same plane but with angle and magnitude in consideration.
Graphing z = -2i on the Argand diagram will look like a segment of the y axis. So we ask ourselves "What angle does this make with the positive x axis? One answer you could ask yourself is -90°! But at the same time, it's 270°! Why do you think this is the case?
What about the magnitude? How far is "-2i" stretched from the typical "i". And the answer is -2! Well... really it gets stretched by a factor of 2 but in the negative direction!
Putting all of this together gives us:
z = |mag|*(cos(angle) + isin(angle))
= 2*cos(270°) + isin(270°)).
To verify, let's consider what cos(270°) and sin(270°) are.
If you graph cos(x) and look at 270°, you get 0.
If you graph sin(x) and look at 270°, you get -1.
So 2*(cos(270°) + isin(270°)) = 2(0 + -1*i) = -2i as expected.
(-5,9) because -6—1=-6+1 which equals -5 and 7—2=7+2 which equals 9
Answer:no
Step-by-step explanation:
Answer:
x = -4
Step-by-step explanation:
-24 = 6x
________
Switch sides:
6x = -24
________
Divide both sides by 6:
6x/6 = -24/6
________
Simplify:
X = -4
