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coldgirl [10]
3 years ago
10

3z + 3/4 - 2z plz help me

Mathematics
1 answer:
Ronch [10]3 years ago
8 0

Answer: z + 3/4

Step-by-step explanation:

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If E F = 7 , A C = 16 , and A F = 9
Vilka [71]

Answers:

CB = 14

GF = 8

FB = 9

EF is parallel to CB

====================================

Explanations:

Points E and F are midpoints of their respective sides. They form the midsegment EF. Because EF is a midsegment, A midsegment is half the length of its parallel counterpart, so CB is two times longer than EF. If EF is 7 units long, then CB = 2*EF = 2*7 = 14

For similar reasons, GF is parallel to AC. If AC = 16, then half of that is GF = (1/2)*AC = 0.5*16 = 8.

FB = FA = 9 as these segments have the same single tickmark to indicate they are the same length

EF is parallel to CB because EF is a midsegment, and this is one of the properties of being a midsegment. We can show that quadrilateral EGBF is a parallelogram to help prove this.

8 0
3 years ago
What is 26/100 in simplest form
Gwar [14]
The simplest form would be 13/50.
Hope it helped!!
4 0
3 years ago
Read 2 more answers
Solve the equation: 9x2+64 = 0. Please show work.
Mice21 [21]
It’s is 82 because you are supposed to do multiply first then add it witch does 82
3 0
3 years ago
A circle has centre (3,0) and radius 5. The line y = 2x + k intersects the circle in two points. Find the set
lara [203]

A circle with center (3,0) and radius 5 has equation

(x-3)^2+y^2=25 \iff x^2 + y^2- 6 x  = 16

If we substitute y=2x+k in this equation, we have

x^2+(2x+k)^2-6x=16 \iff 5x^2+(4k-6)x+k^2-16=0

This equation has two solutions (i.e. the line intersects the circle in two points) if and only if the determinant is greater than zero:

\Delta=b^2-4ac=(4k-6)^2-4\cdot 5\cdot (k^2-16)>0

The expression simplifies to

-4 (k^2 + 12 k - 89)>0 \iff k^2 + 12 k - 89

The solutions to the associated equation are

k^2 + 12 k - 89=0 \iff k=-6\pm 5\sqrt{5}

So, the parabola is negative between the two solutions:

-6-5\sqrt{5}

8 0
3 years ago
Factor the polynomial completely.24x^3-40x^2 45x-75
kumpel [21]
24x^3-40x^2. 45x-75
8x^2(3x-5). 15(3x-5)

(8x^2+15)(3x-5)
3 0
3 years ago
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