The product of multiplying the ones digit of 59 by 853 is 7677 and the product of multiplying the tens digit of 59 by 853 is 42650 and the final product is 50327
<h3>How to determine the product of the numbers?</h3>
The numbers are given as
853 and 59
By using the standard algorithm i.e. the partial product method, we have the following equation
853 * 59 = 853 * (50 + 9)
Open the bracket
So, we have
853 * 59 = 853 * 50 + 853 * 9
Evaluate the products
So, we have
853 * 59 = 42650 + 7677
The above means that the product of multiplying the ones digit of 59 by 853 is 7677 and the product of multiplying the tens digit of 59 by 853 is 42650
Next, we evaluate the sum
853 * 59 = 50327
This means that the final product is 50327
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i don’t know but you could prob use photo math. that would hell
A hole occurs when both numerator and denominator of a rational function have the same factor.
<u>Step-by-step explanation:</u>
While graphing rational function, it has to be converted into the lowest terms by factoring the numerator and denominator. If the numerator and denominator has the same factor, a hole is said to have occurred and to solve the rational function, you have to set the common factor to zero.
After you set it to zero and solve, you obtain the x value which can be then used to find out the value of y.
Answer:
7x+21 = 7x + 21
Step-by-step explanation:
7(x+3)=6-(-7x - 15)
L.H.S
=7(x+3)
=7x+21 (multiply 7 by (x+3))
R.H.S:
=6-(-7x - 15)
= 6+7x+15 (multiply the -ive sign in the bracket)
= 7x + 21 ( adding 15 and 6)
now compare the two sides
7x+21 = 7x + 21 hence we prove that L.H.S= R.H.S
