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3 years ago

2. Which is the largest of these fractions? A. 7/15 B. 4/9 C. 6/11

Mathematics

2 answers:

Pani-rosa [81]3 years ago

8 0

The answer is A 7/15

MakcuM [25]3 years ago

5 0

Answer:C

Step-by-step explanation:

A=4.66666 repeated

B=.4444 repeated

C=.54 repeated

I believe they are checking the biggest decimal. If you take each first number and divide by the second number, you get he decimal, the largest being .54, C.

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Is y=(x+3)^3 a function?

disa [49]

Answer: Yes

Step-by-step explanation:

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3 years ago

Solve -11 - x + = - 5 (2x-3) + 7

garri49 [273]

Answer:

Let's see what to do buddy...

Step-by-step explanation:

_________________________________

$- 11 - x = - 5(2x - 3) + 7$

$- 11 - x = - 10x + 15 + 7$

$- 11 - x = - 10x + 22$

Subtract the sides of the equation plus 11 :

$- x = - 10x + 22 + 11$

$- x = - 10x + 33$

Subtract the sides of the equation plus 10x

$10x - x = 10x - 10x + 33$

$9x = 33$

Divided the sides of the equation by 9 

$\frac{9}{9}x = \frac{33}{9} \\$

$x = \frac{33}{9} = \frac{3 \times 11}{3 \times 3} = \frac{11}{3} \\$

And we're done.

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3 years ago

What is the value of B for the following triangular prism?

Vika [28.1K]

Answer:

56cm is not the answer for sure trust me

Step-by-step explanation:

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5 0

3 years ago

Read 2 more answers

A fruit juice company includes 1.872 ounces of orange juice in a 6.65-ounce bottle of a mixed fruit

BigorU [14]

Answer:

4.778 ounces

Step-by-step explanation:

Given that:

Ounces of orange juice in mixed fruit juice = 1.872

Ounces of mixed fruit juice = 6.65 ounces

Ounces of Mixed fruit juice that is not orange juice :

(Ounces of mixed fruit juice - Ounces of orange juice)

(6.65 - 1.872) ounces

= 4.778 ounces

6 0

2 years ago

Newton's law of cooling is:

Mnenie [13.5K]

Answer:

$t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr$

So it would takes approximately 6.9 hours to reach 32 F.

Step-by-step explanation:

For this case we have the following differential equationÑ

$\frac{du}{dt}= -k (u-T)$

We can reorder the expression like this:

$\frac{du}{u-T} = -k dt$

We can use the substitution $w = u-T$ and $dw =du$ so then we have:

$\frac{dw}{w} =-k dt$

IF we integrate both sides we got:

$ln |w| = -kt +C$

If we apply exponential in both sides we got:

$w = e^{-kt} *e^c$

And if we replace w = u-T we got:

$u(t)= T + C_1 e^{-kt}$

We can also express the solution in the following terms:

$u(t) = (T_i -T_{amb}) e^{kt} +T_{amb}$

For this case we know that $k =-0.15 hr$ since w ehave a cooloing, $T_{i}= 70 F, T_{amb}=11F$ , we have this model:

$u(t) = (70-11) e^{-0.15t} +11$

And if we want that the temperature would be 32F we can solve for t like this:

$32 = 59 e^{-0.15 t} +11$

$21=59 e^{-0.15 t}$

$\frac{21}{59} = e^{-0.15 t}$

If we apply natural logs on both sides we got:

$ln (\frac{21}{59}) =-0.15 t$

$t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr$

So it would takes approximately 6.9 hours to reach 32 F.

7 0

3 years ago