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3 years ago

Can someone help me with this question

Mathematics

1 answer:

Nata [24]3 years ago

4 0

Answer:

no,because I do not know how to answer that

Step-by-step explanation:

sorry

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Is it the right answer

inna [77]

The correct answer would be thirty

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3 years ago

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Select the equation in which you use the inverse property of multiplication to find the solution.

loris [4]

Given:

Equations using properties.

To find:

The equation which use the inverse property of multiplication.

Solution:

Inverse property of multiplication:

The product of any number and its reciprocal is always 1.

Let us select the option which uses inverse property of multiplication.

Option A: $\left(\frac{3}{4} \cdot \frac{4}{3}\right)+7=8$

Inverse of $\frac{3}{4}$ is $\frac{4}{3}$ . Their product is 1.

$$\frac{3}{4} \cdot \frac{4}{3}=1$

This equation uses the inverse property of multiplication.

Option B: $\left(-\frac{7}{8}+\frac{7}{8}\right)+4=4$

Inverse of $\frac{-7}{8}$ is $\frac{8}{-7}$

So, it is not true equation.

Option C: $(-5 \cdot 0)-9=-9$

Inverse of $-5$ is $-\frac{1}{5}$ .

So, it is not true equation.

Option D: $\left[7 \cdot\left(\frac{5}{7}-\frac{4}{7}\right)\right]+8=9$

Here also inverse property is not used.

So, it is not true equation.

Hence the equation use the inverse property of multiplication is

$$\left(\frac{3}{4} \cdot \frac{4}{3}\right)+7=8$ .

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3 years ago

Translate the sentence into a equation

podryga [215]

Answer:

x divided by 4+3=8

Step-by-step explanation: quotient is the division part

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3 years ago

In Hillcrest School, 36% of middle school students are in Grade 6, 31% are in grade 7, and 33% are in grade 8. If a middle schoo

enyata [817]

Answer:

0.64

Step-by-step explanation:

the explanation is in the picture

please like and Mark as brainliest

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3 years ago

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-__y^2-[-5y-y(-7y-9)]-[-y(15y+4)]=0 please help I don’t know how to find the missing coefficient in the blank

Rama09 [41]

Hello,

if y≠0 then

$ay^2-[-5y-y(-7y-9)]-[-y(15y+4)]=0\\\\ay^2-[-5y+7y^2+9y]-[-15y^2-4y]=0\\\\ay^2+5y-7y^2-9y+15y^2+4y=0\\\\ay^2+8y^2=0\\\\(a+8)y^2=0\\\\a=-8\\\\\\$

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3 years ago

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