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katovenus [111]
3 years ago
12

Elizabeth REALLY didn’t study, and she also wrote the formula for dicarbon tetrafluoride as “C2F5”. Describe why her answer is i

ncorrect.
Chemistry
1 answer:
tiny-mole [99]3 years ago
4 0

Answer:

correct formula: C2F4

Explanation:

tetra means 4. There are 2 C and 4 F in dicarbon tetrafluoride.

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1 moles lithium or 6.941 grams
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Draw stearic acid (octadecanoic acid). You do not need to draw hydrogen atoms attached to carbon atoms.
postnew [5]

Answer:

The structure of stearic acid (octadecanoic acid) is shown in the attachment below

Explanation:

Stearic acid is an example of a saturated fatty acid. The structure of stearic acid is shown in the attachment below.

5 0
3 years ago
4. There are 1.9 moles of Oxygen gas at a pressure of 3.50 atm, and the temperature is 65°C. What is the
bonufazy [111]

Answer:

15.06 L

Explanation:

Using the ideal gas law equation:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

According to the information provided in this question,

P = 3.50 atm

n = 1.9 moles

V = ?

T = 65°C = 65 + 273 = 338K

Using PV = nRT

V = nRT/P

V = (1.9 × 0.0821 × 338) ÷ (3.5)

V = 52.725 ÷ 3.5

V = 15.06 L

4 0
3 years ago
Dichotomous Keys are used to identify organisms based on their observed characteristics. Dichotomous means..
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Dichotomous keys consist of a series of statements with two choices in each step that will lead users to the correct identification. So I believe your answer would be A.

7 0
4 years ago
The air bags in automobiles were once inflated by nitrogen gas generated by the rapid decomposition of
Basile [38]

Answer:

1.57 mol NaN₃

Explanation:

  • 2 NaN₃ (s) → 2 Na (s) + 3 N₂ (g)

First we <u>use PV=nRT to calculate the number of N₂ moles that need to be produced</u>:

  • P = 1.07 atm
  • V = 53.4 L
  • n = ?
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • T = 23.7 °C ⇒ 23.7 + 273.16 = 296.86 K

<u>Inputing the data</u>:

  • 1.07 atm * 53.4 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 296.86

And <u>solving for n</u>:

  • n = 2.35 mol N₂

Finally we <u>convert N₂ moles into NaN₃ moles</u>, using <em>the stoichiometric coefficients of the balanced reaction</em>:

  • 2.35 mol N₂ * \frac{2molNaN_3}{3molN_2} = 1.57 mol NaN₃
4 0
3 years ago
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