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Simora [160]
3 years ago
11

41Ca decays by electron capture. The product of this reaction undergoes alpha decay. What is the product of this second decay re

action? 41Ca decays by electron capture. The product of this reaction undergoes alpha decay. What is the product of this second decay reaction? Ti Cl Sc Ar Ca
Chemistry
1 answer:
dimaraw [331]3 years ago
4 0

Answer:

Cl

Explanation:

⁴¹Ca has an atomic number equal to 20, it means that it has 20 protons and 20 electrons ad its neutral state. In the decay by electron capture, it will lose one electron and will become a cation, but the mass (41) and the atomic number will remain the same.

When Ca⁺ undergoes alpha decay, it will lose an alpha particle, which has mass 4 and 2 protons.

⁴¹₂₀Ca⁺ → ³⁷₁₈X⁺ + ⁴₂α

To be stable, X will lose a proton and will become ³⁷₁₇X. The element which has atomic number 17 is chlorine, Cl.

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Dafna11 [192]

The mass percent of oxygen is 32.82%.

<h3>What is a noble gas?</h3>

A noble gas is member of group 18 in the periodic table. The members of this group are known not to be reactive and they do not easily form compounds. However, there have been few compounds of the members of group 18 that have been reported.

Let us now calculate the relative molecular mass of xenon tetraoxide.

Xe + 4 (O)

131 + 4(16) = 195

Given that the mass of oxygen in the compound is 64, the mass  percent of oxygen in xenon tetroxide is obtained from;

64/195 * 100/1

= 32.82%

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5 0
2 years ago
Convert 175 g of H,O into moles.
devlian [24]

Answer:

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3 0
3 years ago
Find the density of metal with a volume 4.0 cm and a mass of 8.0 grams.
olga_2 [115]
D=m/v

so,

d=8.0g/4.0cm

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3 0
3 years ago
Which of the following is an important application of hydrogen bonding
Andrews [41]

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6 0
3 years ago
Read 2 more answers
A 52.0 g of Copper (specific heat=0.0923cal/gC) at 25.0C is warmed by the addition of 299 calories of energy. find the final tem
Leto [7]

Answer : The final temperature of the copper is, 87.29^oC

Solution :

Formula used :

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

where,

Q = heat gained  = 299 cal

m = mass of copper = 52 g

c = specific heat of copper = 0.0923cal/g^oC      

\Delta T=\text{Change in temperature} 

T_{final} = final temperature = ?

T_{initial} = initial temperature = 25^oC

Now put all the given values in the above formula, we get the final temperature of copper.

299cal=52g\times 0.0923cal/g^oC\times (T_{final}-25^oC)

T_{final}=87.29^oC

Therefore, the final temperature of the copper is, 87.29^oC

4 0
4 years ago
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