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Lapatulllka [165]
2 years ago
14

Graham recruited student volunteers to participate in his dissertation study. He set up several times for students to come to a

specified classroom and read various types of instructional materials and to be tested. He ran all of his control conditions first and then for each session he placed all students at the session in the same treatment condition. This is problematic because those who volunteered early are likely different than those who volunteered later. This problem is primarily due to 1. response bias. 2. instrumentation bias. 3. researcher bias. 4. sampling bias.
Mathematics
1 answer:
mart [117]2 years ago
6 0

Answer:

Sampling bias

Step-by-step explanation:

Bias refers a prominent problem in statistical analysis whereby one or more analytical factor are favored than the other during an analysis which should be made random. The problem. With Graham's dissertation study is the fact that he failed to randomlyvplace his subjects or observation in the study groups, favoring a particular group with non random subset. When randomization is ejected or missing from an analysis or study, it becomes less and less representative. Here, allotting early Arrivals Into the treatment group has introduced a sampling bias as those who came later, this will also leads to less reproducibility of experiment.

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Liam works at a zoo. He was looking at some data showing the masses of their
serious [3.7K]

Median won't change, however Mean will fall by 180.

<h3>What do mean and median?</h3>

By summing all the numbers in a data collection and dividing by the total number of values in the set, one may get the mean (average) of the data set. When a data collection is sorted from least to largest, the median represents the midpoint value.

African elephants total 555 in number.

Elephants had a 3800 kg average mass.

Elephants had a 3600 kg median mass.

Lola, the elephant that was the smallest, weighed 2700 kg.

Later, Lola became really ill and lost a lot of weight, reaching a mass of 1800 kg.

What effect will Lola's weight loss have on the mean and median as well as Currently, the median is 3600 and the lowest is 2700.

now 2700 becomes 1800

so Median remains the same as 3600

No change in Median

The mean mass of the elephants was  3800 kg

=> total weight = 5 x 3800 = 19000 kg

2700 kg becomes 1800 kg

Hence new total mass = 19000 - 2700 + 1800 = 181000 kg

New Mean = 18100/5   = 3620  kg

Mean reduced by 3800 - 3620  = 180 kg

No change in Median weight

Mean reduced by 180 kg

To know more about mean and median click the link:

brainly.com/question/12528427

#SPJ1

4 0
1 year ago
Help help help help help help
tamaranim1 [39]

Answer:

1.parenthesis, exponents, multiplication, division, addition, subtraction (pemdas is the Oder of operations)

2. please enjoy my dish and seafood

3.14

4. 4

5. 5

6. 7

7.25

4 0
3 years ago
What is the area<br> of a rectangle driveway measuring 20 feet long and 15 feet wide
goblinko [34]

Answer:

300 squared feet.

Step-by-step explanation:

Area of a rectangle = length × breadth = 20 × 15 = 300 squared feet.

4 0
3 years ago
Read 2 more answers
Which phrase best describes the translation from the graph y=(x-5)^2+7 to the graph of y=(x+1)^2-2
Helga [31]

Start from the parent function f(x)=x^2


In the first case, you are computing


f(x-5)+7


In the second case, you are computing


f(x+1)-2 /tex] There are two translation going on: when you transform [tex] f(x) \to f(x+k), you translate the function horizontally, k units left if k>0 and k units right if k.


On the other hand, when you transform f(x) \to f(x)+k, you translate the function vertically, k units up if k>0 and k units down if k.


So, the first function is the "original" parabola f(x)=x^2, translated 5 units right and 7 units up. Likewise, the second function is the "original" parabola f(x)=x^2, translated 1 units left and 2 units down.


So, the transformation from (x-5)^2+7 to (x+1)^2-2 is: go 6 units to the left and 2 units down

8 0
3 years ago
Read 2 more answers
8 = 4 - 2x<br> - 2x +5 = 17<br> 12= - 3 ( x+ 5)
max2010maxim [7]
8 = 4 - 2x\\8 + 2x = 4\\2x = -4\\x = -2

- 2x +5 = 17\\-2x =12\\x = -6

12= - 3 ( x+ 5)\\12 = -3x -15\\-3x =27\\x= -9
5 0
3 years ago
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