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Lapatulllka [165]
3 years ago
14

Graham recruited student volunteers to participate in his dissertation study. He set up several times for students to come to a

specified classroom and read various types of instructional materials and to be tested. He ran all of his control conditions first and then for each session he placed all students at the session in the same treatment condition. This is problematic because those who volunteered early are likely different than those who volunteered later. This problem is primarily due to 1. response bias. 2. instrumentation bias. 3. researcher bias. 4. sampling bias.
Mathematics
1 answer:
mart [117]3 years ago
6 0

Answer:

Sampling bias

Step-by-step explanation:

Bias refers a prominent problem in statistical analysis whereby one or more analytical factor are favored than the other during an analysis which should be made random. The problem. With Graham's dissertation study is the fact that he failed to randomlyvplace his subjects or observation in the study groups, favoring a particular group with non random subset. When randomization is ejected or missing from an analysis or study, it becomes less and less representative. Here, allotting early Arrivals Into the treatment group has introduced a sampling bias as those who came later, this will also leads to less reproducibility of experiment.

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Find the intercept of g(n)=-2(3n-1)(2n+1)
vaieri [72.5K]
To find the intercepts of this give function of g(n), we have to find both the points present on the axis. That is, X-Intercept axial or axis point and the Y-Intercept axial or axis point and apply the zero factor principle to get the actual points on the graph for both the respective intercepts. Let me make it simpler, by showing the whole process via the LaTeX interpreter equation editor.

The X-Intercept is that actual point present in the graphical interpretation where the Y-axis is taken as zero, this makes us to point out the position of X-Intercept points on its X-axis and Y-axis. Take the variable "n" as the variable of "x", it will not change any context or such, we can take any variables for calculations, it does not hinder the processing of Intercepts for the axial points on a graph.

\boxed{\mathbf{\therefore \quad -2(3x - 1)(2x + 1) = 0}}

By the zero factor principle, both of them can be separately calculated as a zero on their either sides of the expression.

\mathbf{\therefore \quad 3x - 1 = 0}

\mathbf{3x - 1 + 1 = 0 + 1}

\mathbf{3x = 1}

\mathbf{\dfrac{3x}{3} = \dfrac{1}{3}}

\mathbf{\therefore \quad x = \dfrac{1}{3}}

Similarly, for the second X-Intercept point for the value of 0 in the Y-axis or Y axial plane in a 2 dimensional Graphical representation is going to be, As per the zero factor principle:

\mathbf{\therefore \quad 2x + 1 = 0}

\mathbf{2x + 1 - 1 = 0 - 1}

\mathbf{2x = - 1}

\mathbf{\dfrac{2x}{2} = \dfrac{- 1}{2}}

\mathbf{\therefore \quad x = -\dfrac{1}{2}}

Then the X-Intercept here becomes with our provided points as:

\boxed{\mathbf{\underline{X-Intercept: \quad \Bigg(\dfrac{1}{3}, \: 0 \Bigg), \: \: \: \: \Bigg(-\dfrac{1}{2}, \: 0 \Bigg)}}}

Therefore, for our Y-Intercept axial point the X axial plane will instead turn out to be a value with zero on a Graphical representation to obtain the actual points for Y-axis and the Y-Intercept for x = 0 as a point on the graph itself.

Just substitute the value of "0" in "x" axis as a variable on the provided expression. Therefore:

\boxed{\mathbf{= -2(3 \times 0 - 1) (2 \times 0 + 1)}}

\mathbf{y = - 2 (0 - 1) (0 + 1)}

\mathbf{y = - 2 (- 1) (0 + 1)}

\mathbf{y = - 2 (- 1) \times 1}

\mathbf{y = 2 \times 1 \times 1}

\mathbf{\therefore \quad y = 2}

Then, the Y-Intercept would definitely be as per the X-axis lying on the point of zero.

\boxed{\mathbf{\underline{Y-Intercept: \quad \big(0, \: 2 \big)}}}

The final coordinating points for X-Intercept and Y-Intercept for their X-axis and Y-axis will be.

\boxed{\mathbf{\underline{X \: Intercepts: \: \: \Bigg(\dfrac{1}{3}, \: 0 \Bigg), \: \: \: \: \Bigg(-\dfrac{1}{2}, \: 0 \Bigg); \: \: Y \: Intercepts: \: \: \big(0, \: 2 \big)}}}

Hope it helps.
6 0
4 years ago
HEY GUYS I NEED HELP WIT THIS PLZ HELP ME??!! 20 points!!
Otrada [13]

Answer:

The equation for area of a triangle is height multiplied by the base length, divided by 2. So, if the height is 2, and the base is 4, then you multiply the two together, making 8, and then divide it by 2, making the final area 4. So if the dimensions are doubled, then the equation would be 4 times 8 divided by 2. Which is 16. If we do this again with 16 times 8, we will get 128, which when divided by two is 64. This is 4 times 16, just as 16 is 4 times the original answer 4. This means that every time you double the dimensions you will get the original answer multiplied by 4.

Step-by-step explanation:

4 0
3 years ago
Which statement best describes the function h(t) = 210 – 15t?
jonny [76]

Answer:

The answer is b.  

h is the function name; t is the input and h(t) is the output.

The function name is the one outside the parentheses, the input is inside and the output is the whole function.

Step-by-step explanation:

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A square with a side length of 5 inches has a area of 25 in<br><br> true or false
Goryan [66]

Answer:

TRUE

Step-by-step explanation:

5 x 5 = 25 in²

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3 years ago
Consider the following equations x=4/t and y = 4-t^2 a. Solve the equation for y (eliminate the parameter.)​
Nookie1986 [14]

Answer:

y=-16^a/x^2 + 4

Step-by-step explanation:

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