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4 years ago

4) Which step could be completed in order to prepare the system of equations below for the elimination method?

Mathematics

1 answer:

borishaifa [10]4 years ago

3 0

Answer:

Option C - Multiply the 1st equation by 2

Step-by-step explanation:

To find : Which step could be completed in order to prepare the system of equations below for the elimination method?

Solution :

1st equation: $5x-3y=10$

2nd equation: $8x+6y=15$

For elimination method,

We eliminate the y by multiplying 1st equation by 2 and add by 2nd equation.

i.e. 1st equation became $10x-6y=20$

Add with 2nd equation,

$10x-6y+8x+6y=20+15$

$18x=35$

$x=\frac{35}{18}$

Substitute in (1),

$5(\frac{35}{18})-3y=10$

$\frac{175}{18}-3y=10$

$3y=\frac{175}{18}-10$

$3y=\frac{175-180}{18}$

$3y=\frac{-5}{18}$

$y=\frac{-5}{54}$

Therefore, the step could be completed in order to prepare the system of equations below for the elimination method is option C.

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What expression is equivalent to ^3 square root of 2y^3 times 7 square root of 18y

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Answer:

$\sqrt[3]{2y^3} * 7\sqrt{18y} = 21(y^{\frac{3}{2}})(2^{\frac{5}{6}})$

Step-by-step explanation:

The question is poorly formatted.

Given

$\sqrt[3]{2y^3} * 7\sqrt{18y}$

Required

Derive an equivalent expression

$\sqrt[3]{2y^3} * 7\sqrt{18y}$

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$\sqrt[3]{2y^3} * 7\sqrt{9 * 2y}$

Split the expression as follows:

$\sqrt[3]{2y^3} * 7\sqrt{9} * \sqrt{2y}$

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$\sqrt[3]{2y^3} * 7*3 * \sqrt{2y}$

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$21*\sqrt[3]{2y^3} * \sqrt{2y}$

The cube root can be rewritten to give:

$21*\sqrt[3]{2}*\sqrt[3]{y^3} * \sqrt{2y}$

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$21*\sqrt[3]{2} * y * \sqrt{2y}$

Rewrite as:

$21y *\sqrt[3]{2} * \sqrt{2y}$

Split $\sqrt{2y$

$21y *\sqrt[3]{2} * \sqrt{2} * \sqrt{y}$

Collect Like Terms

$21y*\sqrt{y} *\sqrt[3]{2} * \sqrt{2}$

Represent in index form

$21y*y^{\frac{1}{2}} *2^\frac{1}{3} *2^\frac{1}{2}$

Apply law of indices

$21*y^{1+\frac{1}{2}} *2^{\frac{1}{3} +\frac{1}{2} }$

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$21*y^{\frac{3}{2}} *2^{\frac{5}{6}}$

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Hence:

$\sqrt[3]{2y^3} * 7\sqrt{18y} = 21(y^{\frac{3}{2}})(2^{\frac{5}{6}})$

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Step-by-step explanation:

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