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Ierofanga [76]
4 years ago
10

4) Which step could be completed in order to prepare the system of equations below for the elimination method?

Mathematics
1 answer:
borishaifa [10]4 years ago
3 0

Answer:

Option C - Multiply the 1st equation by 2

Step-by-step explanation:

To find : Which step could be completed in order to prepare the system of equations below for the elimination method?

Solution :

1st equation: 5x-3y=10

2nd equation: 8x+6y=15

For elimination method,

We eliminate the y by multiplying 1st equation by 2 and add by 2nd equation.

i.e. 1st equation became  10x-6y=20

Add with 2nd equation,

10x-6y+8x+6y=20+15

18x=35

x=\frac{35}{18}

Substitute in (1),

5(\frac{35}{18})-3y=10

\frac{175}{18}-3y=10

3y=\frac{175}{18}-10

3y=\frac{175-180}{18}

3y=\frac{-5}{18}

y=\frac{-5}{54}

Therefore, the step  could be completed in order to prepare the system of equations below for the elimination method is option C.

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Answer:

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4 0
3 years ago
I need help on this please help!
Licemer1 [7]

Answer:

(b)0.56

(c)0.38

Step-by-step explanation:

(a)

P(Ben Pass) =0.8

Therefore: P(Ben fails)=1-0.8 =0.2

P(Tom Pass) =0.7

Therefore: P(Tom fails)=1-0.7 =0.3

See attached for the completed tree diagram

(b)Probability that both will pass

P(both will pass)=P(Ben pass and Tom pass)

=P(Ben pass) X P(Tom pass)

=0.8 X 0.7

=0.56

(c)The probability that only one of them will pass

Since either Tom or Ben can pass, we have:

P(only one of them will pass)

=P(Ben pass and Tom fails OR Ben Fails and Tom Pass)

=P(Ben pass and Tom fails)+P(Ben Fails and Tom Pass)

=(0.8 X 0.3) + (0.2 X 0.7)

=0.24 + 0.14

=0.38

8 0
3 years ago
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