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andrew11 [14]
3 years ago
14

Solve the compound inequality 2(x-2)+7>-1 and 5-4x>9

Mathematics
1 answer:
ohaa [14]3 years ago
3 0

Answer:

1) x > -2

2) x < -1

Step-by-step explanation:

1) 2(x - 2) + 7 > -1

2x - 4 + 7 > -1

2x + 3 > -1

2x > -4

x > -2

2) 5 - 4x > 9

-4x > 4

x < -1

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A house painter has an annual income of $35,000 and paid $2,500 in income tax. What percent of her income is the income tax?
almond37 [142]

Answer:

The 7.14% of her income is the income tax .

Step-by-step explanation:

Formula

Percentage = \frac{Part\ value\times 100}{Total\ value}

As given

A house painter has an annual income of $35,000 and paid $2,500 in income tax.

Here

Part value = $2500

Total value = $35000

Put in the formula

Percentage = \frac{2500\times 100}{35000}

Percentage = \frac{250000}{35000}

Percentage = 7.14\ (Approx)

Therefore the 7.14% of her income is the income tax .

3 0
3 years ago
Two boats leave a dock at the same time. One boat travels south at 32 mi divided by hr32 mi/hr and the other travels east at 60
TEA [102]

Answer: the rate at which the distance between the boats is​ increasing is 68 mph

Step-by-step explanation:

The direction of movement of both boats forms a right angle triangle. The distance travelled due south and due east by both boats represents the legs of the triangle. Their distance apart after t hours represents the hypotenuse of the right angle triangle.

Let x represent the length the shorter leg(south) of the right angle triangle.

Let y represent the length the longer leg(east) of the right angle triangle.

Let z represent the hypotenuse.

Applying Pythagoras theorem

Hypotenuse² = opposite side² + adjacent side²

Therefore

z² = x² + y²

To determine the rate at which the distances are changing, we would differentiate with respect to t. It becomes

2zdz/dt = 2xdx/dt + 2ydy/dt- - - -- - -1

One travels south at 32 mi/h and the other travels east at 60 mi/h. It means that

dx/dt = 32

dy/dt = 60

Distance = speed × time

Since t = 0.5 hour, then

x = 32 × 0.5 = 16 miles

y = 60 × 0.5 = 30 miles

z² = 16² + 30² = 256 + 900

z = √1156

z = 34 miles

Substituting these values into equation 1, it becomes

2 × 34 × dz/dt = (2 × 16 × 32) + 2 × 30 × 60

68dz/dt = 1024 + 3600

68dz/dt = 4624

dz/dt = 4624/68

dz/dt = 68 mph

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