Answer
given,
height of object = 2.7 cm
distance left of lens (u₁)= 20 cm
focal length of lens(f₁)= 10 cm
the distance of image
v₁ = 20 cm
magnification of first lens
m₁ = -1
distance of object from the second lens
u₂ = 52-20 = 32 cm
f₂ = 48 cm
now,
v₁ = 624 cm
magnification of first lens
m₁ = -12
total magnification
m = m₁ m₂
m = (-1)(-12)
m = 12
height of image
h' = -32.4 cm
a) distance between image and second lens is equal to 624 cm
b) height of image is equal to 32.4 cm