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vladimir2022 [97]
3 years ago
12

How does a heat pump resemble a refrigeration system?

Physics
1 answer:
REY [17]3 years ago
3 0
A heat pump is a device that is capable of transferring heat energy from a source of heat to what is known as the heat sink. It also moves thermal energy in the opposite direction of a spontaneous heat transfer through heat absorption from a cold space and releasing it to a warmer space.

When a heat pump is being utilized for heating, it employs the same principle with that of the refrigeration cycle used by an air conditioner or a refrigerator, but in the opposite direction since it releases heat into a conditioned space rather than the surrounding environment. Moreover, heat pump resembles much as refrigeration since it has the same components with the latter except for the presence of a reverse valve.
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Andrea asked her brother to take a 4 ft floating raft out of the water near the wave-swept shore. Using this raft as a measuring
lutik1710 [3]

Answer:

176ft/s

Explanation:

Speed of a wave is a function of the frequency and wavelength of the wave. It is expressed mathematically as:

V = fλ where:

V is the speed of the wave

f is the frequency

λ is the wavelength

Given f = 16Hz, λ = 11ft

V = 16×11

V = 176ft/s

7 0
4 years ago
Light with a wavelength of 494 nm in vacuo travels from vacuum to water. Find the wavelength of the light inside the water in nm
Mamont248 [21]

Answer:

370.6 nm

Explanation:

wavelength in vacuum = 494 nm

refractive index of water with respect to air = 1.333

Let the wavelength of light in water is λ.

The frequency of the light remains same but the speed and the wavelength is changed as the light passes from one medium to another.

By using the definition of refractive index

n = \frac{wavelength in air}{wavelength in water}

where, n be the refractive index of water with respect to air

By substituting the values, we get

1.333 = \frac{494}{\lambda }

λ = 370.6 nm

Thus, the wavelength of light in water is 370.6 nm.

8 0
3 years ago
If you mix 100 g of ice at 0 ∘c with 100 g of boiling water at 100 ∘c in a perfectly insulated container, the final stabilized t
loris [4]

The final stabilized temperature will be between 0 °C and 50 °C.

<h3>Calorimetry:</h3>

The enthalpy of fusion of ice is 334 J/g. The specific heat of water is 4.2 J/g.

To cool 100 g of water from 100 °C to 0 °C would require the removal of

4.2 x 100 x 100 = 42000 J.

To melt the ice would require the addition of

334 x 100 = 33400 J

∴ 42000  > 33400 thus you can melt all the ice and have some heat to spare, specifically 42000 - 33400 = 8600 J

Now use this to warm up 100+100 = 200 g of water at 0 °C

The final stabilized temperature;

8600 / (200 x 4.2) = 10.23 °C

Therefore, the final stabilized temperature is 10.23 °C

Learn more about Calorimetry here:

brainly.com/question/1989313

#SPJ4

4 0
2 years ago
A 20-kg object is subjected to three forces which produce an acceleration a = -8 m.s^-2 i + 6.0 m.s^-2 j on the object. Two of t
lana66690 [7]

Answer:

F₃ = -151 N i + 96 N j

Explanation:

Newton's second law:

∑F = m*a Formula (1)

∑F : algebraic sum of the forces in Newton (N)

m : mass s (kg)

a : acceleration  (m/s²)

Forces acting on the object

F₁= 3.0 N i + 16.0 N j

F₂ = -12.0 N i+ 8.0 N j

F₃ = F₃x N i +F₃ y N j

x component of the net force on the object

Fx=F₁x+F₂x+F₃ x

Fx = 3.0 N-12.0 N +F₃x

Fx = F₃x - 9 N

y component of the net force on the object

Fy=F₁y+F₂y+F₃ y

Fy =16.0 N+ 8.0 N +F₃y

Fy = F₃y + 24 N

Newton's second law to the object:

a = -8 m/s² i + 6.0 m/s² j

∑Fx = m*ax    m=20 kg , ax = -8 m/s²

F₃x - 9 = 20 *(-8)

F₃x = -160+9

F₃x = -151 N

∑Fy = m*ay    m=20 kg , ay = 6 m/s²

F₃y + 24 =20*( 6 )

F₃y =120 - 24

F₃y = 96 N

F₃ = -151 N i + 96 N j

7 0
3 years ago
A small bubble rises from the bottom of a lake, where the temperature and pressure are 4°C and 3.0 atm, to the water's surface,
qwelly [4]

Answer:

7.13mL

Explanation:

P₁V₁T₁ = P₂V₂T₂

P₁ = 3atm , V₁ = 2.1 mL , T₁ = 273 + 4 =277K

P₂ = 0.95atm , V₂ = ? , T₂ = 273 + 25 =298K

V₂ = P₁V₁T₂ / P₂T₁

V₂ = (3atm)(2.1 mL )(298K) / (0.95atm)(277K)

V₂ = 7.13mL

6 0
4 years ago
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