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Dimas [21]
3 years ago
10

As you stand near a railroad track, a train passes by at a speed of 31.7 m/s while sounding its horn at a frequency of 218 Hz. W

hat frequency do you hear as the train approaches you and what frequency while it recedes?
Physics
1 answer:
Darya [45]3 years ago
6 0

Explanation:

Given that,

Frequency of train horn, f = 218 Hz

Speed of train, v_t = 31.7 m/s

The speed of sound, V = 344 m/s (say)

The speed of the observed person, V_o=0\ m/s

(a) When the train approaches you, the Doppler's effect gives the frequency as follows :

f'=f(\dfrac{V}{V-v_t})\\\\f'=218\times (\dfrac{344}{344-31.7})\\\\f'=240.12\ Hz

(b) When the train moves away from you, the Doppler's effect gives the frequency as follows :

f'=f(\dfrac{V}{V+v_t})\\\\f'=218\times (\dfrac{344}{344+31.7})\\\\f'=199.6\ Hz

Hence, this is the required solution.

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Let m1 and m2 be the mass per unit length of the wires

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Since the tension and mass of the wire is the same

m1= m2= m.

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m2 =M/4l( since the second is tour times as far apart)

V1 = 290m/s(velocity in shorter wire)

V2 is the velocity of the longer wire.

V1 = √T/(m/l)

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V2 = √4Tl/m

V2²= 4Tl/m... 2

Dividing equation 1 by 2 we have;

290²/V2² = {Tl/m}/{4Tl/m}

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Cross multiplying we have;

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Learn more about work done here: brainly.com/question/8119756

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