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Vladimir [108]
3 years ago
6

8. Why would it be a bad idea to make coins made of sodium metal?

Chemistry
1 answer:
Elina [12.6K]3 years ago
5 0

Answer:

Sodium reacts with the oxygen in air. It reacts vigorously with oxygen and the moisture that is already present in the air and thus catches fire.

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The symbol equation for combustion of a hydrocarbon is shown below. What number should go before the water product in order to b
almond37 [142]

Answer:

4

Explanation:

Since there are 3 carbons on the left side, make the coefficient of CO2 equal to 3.

Also, since there are 8 hydrogen on the left side, make the coefficient of H2O equal to 4.

This means there are 3(2)+4=10 oxygen atoms on the right, making the coefficient of O2 equal to 5.

5 0
3 years ago
If an acid has a ka=1.6x10^-10, what is the acidity of the solution?
LUCKY_DIMON [66]
The information given in the question is not enough to determine the acidity of the solution. This is because, acidity can only be found with the equation: pH = -log [H+].
 In order to determine the acidity of the solution, the half titration point value is needed, this will make it possible to determine the value of H30+.  If the half point titration value is known, then Ka will be equivalent to pH and the value will be evaluated using the equation: - log (1.6 * 10^-10).
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3 years ago
One afternoon you were riding in your car and your mother had to slam on the brakes to prevent hitting a squirrel.
lianna [129]

Answer:

that squirrel would be dead if it was my mom

Explanation:

6 0
3 years ago
Magnesium is the limiting reactant in this experiment. Calculate the theoretical yield of MgO for each trial.
liq [111]

/watch?v=DLzxrzFCyOs

6 0
3 years ago
In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide Al2O3 dissolved in molten c
gtnhenbr [62]

Answer:

1.13 × 10⁶ g

Explanation:

Let's consider the reduction of aluminum (III) from Al₂O₃ to pure aluminum.

Al³⁺ + 3 e⁻ → Al

We can establish the following relations:

  • 1 Ampere = 1 Coulomb / second
  • The charge of 1 mole of electrons is 96,468 c (Faraday's constant)
  • 1 mole of Al is produced when 3 moles of electrons circulate
  • The molar mass of Al is 26.98 g/mol.

The mass of aluminum produced under these conditions is:

90.0 s \times \frac{1s}{620c} \times \frac{96,468c}{1mole^{-} } \times \frac{3mole^{-}}{1molAl} \times \frac{26.98gAl}{1molAl} =1.13 \times 10^{6} g Al

6 0
4 years ago
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