This exercise deals with safety issues in the Freezing Point Depression experiment. Choose the answer that best completes each s
1 answer:
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Answer : The value of rate constant at temperature 119 K is 2.46 E-29
Explanation :
As we are the rate law expression as:
..........(1)
The general rate law expression will be:
............(2)
By comparing equation 1 and 2 we get:
Now we have to calculate the rate constant at temperature 119 K.
According to the Arrhenius equation,
or,
where,
= rate constant at
=
= rate constant at
= ?
= activation energy for the reaction = 80.0 kJ/mole = 80000 J/mole
R = gas constant = 8.314 J/mole.K
= initial temperature = 500 K
= final temperature = 119 K
Now put all the given values in this formula, we get:
Therefore, the value of rate constant at temperature 119 K is 2.46 E-29