How much would you need to weigh out in order to have 0.2moles of magnesium atoms?
1 answer:
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Answer:
0.1357 M
Explanation:
(a) The balanced reaction is shown below as:
(b) Moles of can be calculated as:
Or,
Given :
For :
Molarity = 0.1450 M
Volume = 10.00 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 10×10⁻³ L
Thus, moles of :
Moles of = 0.00145 moles
From the reaction,
1 mole of react with 2 moles of NaOH
0.00145 mole of react with 2*0.00145 mole of NaOH
Moles of NaOH = 0.0029 moles
Volume = 21.37 mL = 21.37×10⁻³ L
Molarity = Moles / Volume = 0.0029 / 21.37×10⁻³ M = 0.1357 M
No, because the appearance has nothing to do with system as well as the fact that appearance is only how it looks
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(Btw, that toga picture is like... ughhhh!) hope this helps you ♥︎☀︎☁︎♨︎