All categories

4 years ago

How are energy and work related?

Chemistry

1 answer:

kipiarov [429]4 years ago

4 0

Answer:

Explanation:

When work is done, energy is transferred between systems, or transformed from one type of energy into another type. Energy shares the same units of measure as work.

You might be interested in

How many molecules of water are there in 1 gram of water

alisha [4.7K]

Answer:

6.022*1023

Explanation:

3 0

3 years ago

Read 2 more answers

Determine the energy released per kilogram of fuel used. given mev per reaction, calculate energy in joules per kilogram of reac

tatuchka [14]

The energy released in nuclear reactions are far larger than that released in chemical reactions due to the release of nuclear energy from the nucleus.

<h3>Why is the energy released in a reaction?</h3>

Energy is released in a reaction due to the breaking of bonds are well as formation of bonds.

The quantity of energy released in reactions differs according to the reaction type involved.

When compared to chemical reactions, the energy released in nuclear reactions are very much higher because of the changes that occurs in the nucleus of the atoms involving nuclear energy.

The energy, E released in nuclear reactions is given by the formula below:

$E = mc^{2}$

where m is the mass of the substance and c is the speed of light.

Therefore, the energy released in nuclear reactions are far larger than that released in chemical reactions.

Learn more about nuclear reactions at: brainly.com/question/984564

6 0

2 years ago

Consider the reaction to produce methanolCO(g) + 2H2 (g) <-----> CH3OHAn equilibrium mixture in a 2.00-L vessel is found t

MariettaO [177]

Answer : The value of $K_c$ of the reaction is 10.5 and the reaction is product favored.

Explanation : Given,

Moles of $CH_3OH$ at equilibrium = 0.0406 mole

Moles of $CO$ at equilibrium = 0.170 mole

Moles of $H_2$ at equilibrium = 0.302 mole

Volume of solution = 2.00 L

First we have to calculate the concentration of $CH_3OH,CO\text{ and }H_2$ at equilibrium.

$\text{Concentration of }CH_3OH=\frac{\text{Moles of }CH_3OH}{\text{Volume of solution}}=\frac{0.0406mole}{2.00L}=0.0203M$

$\text{Concentration of }CO=\frac{\text{Moles of }CO}{\text{Volume of solution}}=\frac{0.170mole}{2.00L}=0.085M$

$\text{Concentration of }H_2=\frac{\text{Moles of }H_2}{\text{Volume of solution}}=\frac{0.302mole}{2.00L}=0.151M$

Now we have to calculate the value of equilibrium constant.

The balanced equilibrium reaction is,

$CO(g)+2H_2(g)\rightleftharpoons CH_3OH(g)$

The expression of equilibrium constant $K_c$ for the reaction will be:

$K_c=\frac{[CH_3OH]}{[CO][H_2]^2}$

Now put all the values in this expression, we get :

$K_c=\frac{(0.0203)}{(0.085)\times (0.151)^2}$

$K_c=10.5$

Therefore, the value of $K_c$ of the reaction is, 10.5

There are 3 conditions:

When $K_{c}>1$ ; the reaction is product favored.

When $K_{c}$ ; the reaction is reactant favored.

When $K_{c}=1$ ; the reaction is in equilibrium.

As the value of $K_{c}>1$ . So, the reaction is product favored.

7 0

3 years ago

PLEASE HELP with these problems ASAP!!! 30 points!!

ipn [44]

Answer:

which?........................

5 0

3 years ago

URGENT PLEASE HELP!!!

mote1985 [20]

Even though two grams seemed to disappear or vanish, the law of conversation of mass still holding true. Mercuric oxide, when heated, forms a gas of mercury and oxygen. During the investigation, some gas could have escaped or evaporated.

5 0

3 years ago

Read 2 more answers