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Ainat [17]
2 years ago
7

Lisa and her 17 classmates are donating money to a local charity. Each student will donate $5.25. How much money are Lisa and he

r classmates donating altogether?
Mathematics
2 answers:
masya89 [10]2 years ago
8 0

Answer:

$94.50

Step-by-step explanation:

Total No. of students = Lisa(1) + 17 classmates = 1+17 = 18

Money donated by 1 student = $5.25

Money donated by 18 Students = 18*5.25 = $94.50

ch4aika [34]2 years ago
4 0
$94.50
money donated 1 student=$5.25
17+5.25=$94.50
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If the angle NME = x+97, the angle EML = x+66, and the angle NML = 141, find the angle EML
defon

Answer:

∠ EML = 94°

Step-by-step explanation:

See the attached diagram.

The three angles ∠ NME, ∠ EML and ∠ NML together make 360°.

Now, ∠ NME = x + 97, ∠ EML = x + 66 and ∠ NML = 141°

Hence, (x + 97) + ( x + 66) + 141 = 360

⇒ 2x + 304 = 360

⇒ 2x = 56

⇒ x = 28

So, ∠ EML = x + 66 = 28 + 66 = 94° (Answer)

6 0
3 years ago
A bank's electronic management system lacks the ability to protect a client's confidential information. To what type of risk doe
ankoles [38]
First one
market risk
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3 0
3 years ago
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What are the roots of this equation? x2-4x+9=0
zysi [14]

Considering the definition of zeros of a function, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

<h3>Zeros of a function</h3>

The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.

In summary, the roots or zeros of the quadratic function are those values ​​of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.

In a quadratic function that has the form:

f(x)= ax² + bx + c

the zeros or roots are calculated by:

x1,x2=\frac{-b+-\sqrt{b^{2}-4ac } }{2a}

<h3>This case</h3>

The quadratic function is f(x) = x² + 4x +9

Being:

  • a= 1
  • b= 4
  • c= 9

the zeros or roots are calculated as:

x1=\frac{-4+\sqrt{4^{2}-4x1x9 } }{2x1}

x1=\frac{-4+\sqrt{16-36 } }{2x1}

x1=\frac{-4+\sqrt{-20 } }{2x1}

and

x2=\frac{-4-\sqrt{4^{2}-4x1x9 } }{2x1}

x2=\frac{-4-\sqrt{16-36 } }{2x1}

x2=\frac{-4-\sqrt{-20} }{2x1}

If the content of the root is negative, the root will have no solution within the set of real numbers. Then \sqrt{-20} has no solution.

Finally, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

Learn more about the zeros of a quadratic function:

brainly.com/question/842305

brainly.com/question/14477557

#SPJ1

6 0
1 year ago
Use 1/2 of preparation now. In 24 hours use the remaining amount of preparation there is 8 ounces of preparation in the bottle.
7nadin3 [17]
I’ll use 1/2 for each Just multiply the 1/2 by the 8
7 0
3 years ago
Use benchmarks <br> 3\5 + 3\17
nadya68 [22]

Answer:

66/85

Step-by-step explanation:

3 0
2 years ago
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