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ikadub [295]
3 years ago
15

Consider two objects whose masses are 100 g and 200 g. The 100 g object strikes

Chemistry
1 answer:
Murljashka [212]3 years ago
8 0

Answer:

Soo B

because.

Explanation:

500 N because the reaction force is equal in magnitude to the action force.

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How much 5.50M NaOH must be added to 680.0 mL of a buffer that is 0.0215 M acetic acid and 0.0270 M sodium acetate to raise the
Lelu [443]

5.50M NaOH must be added to 680.0 mL of a buffer, The amount of NaOH  is mathematically given as

V=2.107mL

<h3>What is the volume of 5.50M NaOH?</h3>

Generally, the equation for Chemical Reaction is mathematically given as

CH3COOH+OH^{-} ⇄ CHCOO^{-} + H2O

Therefore

pka=-log(1.8*10{-5})

pKa=5-0.25527

pKa=4.3447

Hence

pH=pKa+log\frac{CH3COO}{CH3COOH}\\\\0.75=4.7447+log\frac{0.01564+x}{0.01428-x}

x=0.0115898

Volume of NaOH

V=0.0021072L

V=2.107mL

Read more about Chemical Reaction

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5 0
2 years ago
Elements x and y form 2 binary compounds. In the first 14.0 g of x combines with 3.0 g of y. In the second, 7.00 g of x combine
Roman55 [17]

second compound

Let molar mass of x is = X

Let molar mass of y is = Y

Moles of x in second compound = Mass / molar mass = 7 / X

Moles of y in second compound = Mass / molar mass = 4.5 / Y

For second compound  

7 / X : 4.5/ Y = 1:1

Therefore

X / Y = 7/4.5

Y / X = 4.5/ 7

The mass of x in first compound = 14g

moles of x in first compound = 14/X

Mass of y in first compound = 3

moles of y in first compound = 3 / Y

14 / X : 3/ Y = 14Y / 3X = 14 X 4.5 / 3 X 7 = 3 :1

Thus molar ratio in first compound = moles of x / Moles of y = 3:2

Formula = x3y

6 0
3 years ago
In which organ in <br> a earthworm can I find the content to be most ground up and why
Yanka [14]
The intestines

By the time food has reached the intestines, it has already passed through the gizzard (where it is ground up) and has nutritious pieces absorbed before waste is passed to the excretory system.
8 0
3 years ago
What happens when an electron absorbs energy?
Leto [7]
Gets exited and moves at a faster constant speed

7 0
4 years ago
A sample of 2.00 mol of gas in a 10.00 L container is at 45.0 °C. What is the pressure (in atm) of the gas?
Firdavs [7]

Answer:

5.22 atm

Explanation:

The following data were obtained from the question:

Number of mole (n) = 2 moles

Volume (V) = 10 L

Temperature (T) = 45 °C

Pressure (P) =?

Next, we shall convert 45 °C to Kelvin temperature. This can be obtained as follow:

Temperature (K) = Temperature (°C) + 273

T (K) = T (°C) + 273

T (°C) = 45 °C

T(K) = 45 °C + 273

T (K) = 318 K

Finally, we shall determine the pressure of the gas by using the ideal gas equation as shown below:

Number of mole (n) = 2 moles

Volume (V) = 10 L

Temperature (T) = 318 K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =.?

PV = nRT

P x 10 = 2 x 0.0821 x 318

Divide both side by 10

P = (2 x 0.0821 x 318) /10

P = 5.22 atm

Therefore, the pressure of the gas is 5.22 atm

6 0
3 years ago
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