5.50M NaOH must be added to 680.0 mL of a buffer, The amount of NaOH is mathematically given as
V=2.107mL
<h3>What is the volume of 5.50M NaOH?</h3>
Generally, the equation for Chemical Reaction is mathematically given as
CH3COOH+OH^{-} ⇄ CHCOO^{-} + H2O
Therefore
pka=-log(1.8*10{-5})
pKa=5-0.25527
pKa=4.3447
Hence
x=0.0115898
Volume of NaOH
V=0.0021072L
V=2.107mL
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second compound
Let molar mass of x is = X
Let molar mass of y is = Y
Moles of x in second compound = Mass / molar mass = 7 / X
Moles of y in second compound = Mass / molar mass = 4.5 / Y
For second compound
7 / X : 4.5/ Y = 1:1
Therefore
X / Y = 7/4.5
Y / X = 4.5/ 7
The mass of x in first compound = 14g
moles of x in first compound = 14/X
Mass of y in first compound = 3
moles of y in first compound = 3 / Y
14 / X : 3/ Y = 14Y / 3X = 14 X 4.5 / 3 X 7 = 3 :1
Thus molar ratio in first compound = moles of x / Moles of y = 3:2
Formula = x3y
The intestines
By the time food has reached the intestines, it has already passed through the gizzard (where it is ground up) and has nutritious pieces absorbed before waste is passed to the excretory system.
Gets exited and moves at a faster constant speed
Answer:
5.22 atm
Explanation:
The following data were obtained from the question:
Number of mole (n) = 2 moles
Volume (V) = 10 L
Temperature (T) = 45 °C
Pressure (P) =?
Next, we shall convert 45 °C to Kelvin temperature. This can be obtained as follow:
Temperature (K) = Temperature (°C) + 273
T (K) = T (°C) + 273
T (°C) = 45 °C
T(K) = 45 °C + 273
T (K) = 318 K
Finally, we shall determine the pressure of the gas by using the ideal gas equation as shown below:
Number of mole (n) = 2 moles
Volume (V) = 10 L
Temperature (T) = 318 K
Gas constant (R) = 0.0821 atm.L/Kmol
Pressure (P) =.?
PV = nRT
P x 10 = 2 x 0.0821 x 318
Divide both side by 10
P = (2 x 0.0821 x 318) /10
P = 5.22 atm
Therefore, the pressure of the gas is 5.22 atm
