<span>copper(II) chloride octahydrate</span>
Answer: a) 
is the limiting reagent
b) 3.59 g
c) 11.6g
Explanation:
To calculate the moles :
According to stoichiometry :
a) 9 moles of require= 4 moles of 
Thus 0.15 moles of will require=
of 
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
b) As 9 moles of give = 8 moles of
Thus 0.15 moles of give =
of
Mass of 
c) As 9 moles of give = 3 moles of 
Thus 0.15 moles of give =
of
Mass of 
Answer:
You just have to take the periodic table of the elements, take the element that interests you. Then, you look at the formula of the element, at the top left you find the number of neutrons and protons and at the bottom left you find the number of protons. Then you just have to make the number from the top left minus the number from the bottom left.
Explanation:
Explanation:
a material system in which mass or energy can be lost to or gained from the environment.
