How much 5.50M NaOH must be added to 680.0 mL of a buffer that is 0.0215 M acetic acid and 0.0270 M sodium acetate to raise the

Question

2 years ago

9

pH to 5.75?

1 answer:

Lelu [443] · Answer 1 · 2023-10-12T08:35:09+03:00

5.50M NaOH must be added to 680.0 mL of a buffer, The amount of NaOH is mathematically given as

V=2.107mL

<h3>What is the volume of 5.50M NaOH?</h3>

Generally, the equation for Chemical Reaction is mathematically given as

CH3COOH+OH^{-} ⇄ CHCOO^{-} + H2O

Therefore

pka=-log(1.8*10{-5})

pKa=5-0.25527

pKa=4.3447

Hence

$pH=pKa+log\frac{CH3COO}{CH3COOH}\\\\0.75=4.7447+log\frac{0.01564+x}{0.01428-x}$

x=0.0115898

Volume of NaOH

V=0.0021072L

V=2.107mL