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inn [45]
3 years ago
11

Evaluate 3x - 2 when x=7

Mathematics
1 answer:
natali 33 [55]3 years ago
6 0

Answer:

See below

Step-by-step explanation:

<u>Part 1:</u>

= 3x - 2

Given that x = 7

= 3(7) - 2

= 21 - 2

\boxed{= \ 19}

<u>Part 2:</u>

= 3x + 7

3 => Coefficient

x => variable

\boxed{7 => constant}

<u>Part 3:</u>

More than => +

So,

<u>The expression is:</u>

= 12 + b

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
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sukhopar [10]

Answer:

(a) 144

(b) 117

(c) 360

(d) 588

(e) 5472

Step-by-step explanation:

To find the LCM of two numbers, first find the prime factorization of each number. Then the LCM is the product of common and not common factors with the larger exponent.

2.

(a)

72 = 2^3 \times 3^2

144 = 2^4 \times 3^2

LCM = 2^4 \times 3^2 = 8 \times 9 = 144

(b)

39 = 3 \times 13

117 = 3^2 \times 13

LCM = 3^2 \times 13 = 117

(c)

72 = 2^3 \times 3^2

90 = 2 \times 3^2 \times 5

LCM = 2^3 \times 3^2 \times 5 = 360

(d)

84 = 2^2 \times 3 \times 7

147 = 3 \times 7^2

LCM = 2^2 \times 3 \times 7^2 = 588

(e)

152 = 2^3 \times 19

288 = 2^5 \times 3^2

LCM = 2^5 \times 3^2 \times 19 = 5472

6 0
3 years ago
I need help with this if you get it right I will mark you
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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