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EastWind [94]
3 years ago
10

PLASE ANSWER THIS QUESTION ​I GIVE YOU 18 POINTS

Mathematics
1 answer:
sukhopar [10]3 years ago
6 0

Answer:

(a) 144

(b) 117

(c) 360

(d) 588

(e) 5472

Step-by-step explanation:

To find the LCM of two numbers, first find the prime factorization of each number. Then the LCM is the product of common and not common factors with the larger exponent.

2.

(a)

72 = 2^3 \times 3^2

144 = 2^4 \times 3^2

LCM = 2^4 \times 3^2 = 8 \times 9 = 144

(b)

39 = 3 \times 13

117 = 3^2 \times 13

LCM = 3^2 \times 13 = 117

(c)

72 = 2^3 \times 3^2

90 = 2 \times 3^2 \times 5

LCM = 2^3 \times 3^2 \times 5 = 360

(d)

84 = 2^2 \times 3 \times 7

147 = 3 \times 7^2

LCM = 2^2 \times 3 \times 7^2 = 588

(e)

152 = 2^3 \times 19

288 = 2^5 \times 3^2

LCM = 2^5 \times 3^2 \times 19 = 5472

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Answer:

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4 years ago
What is the oblique asymptote of the function f(x) x^2+x-2/x+1
Mamont248 [21]
f(x)=\displaystyle\frac{x^2+x-2}{x+1}=\frac{x(x+1)-2}{x+1}=x-\frac{2}{x+1}


\displaystyle\lim_{x\to\infty}\left\{f(x)-x \right\}=\lim_{x\to\infty}\frac{2}{x+1}=\lim_{x\to\infty}\frac{\displaystyle\frac{2}{x}}{1+\displaystyle\frac{1}{x}}
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3 0
3 years ago
<img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20-%2014x%20%2B%2024" id="TexFormula1" title="2x^{2} - 14x + 24" alt="2x^{2} - 14
s344n2d4d5 [400]

Answer:

Factorized

      =(2x-8)(x-3)

Roots : 4 , 3

Step-by-step explanation:

If it is to factorize :

2x^2 - 14x + 24 = 2x^2 -6x-8x +24

                     =2x(x-3)-8(x-3)\\=(2x-8)(x-3)

If it is to solve for x :

2x^2 -1 4x + 24 = 0\\(2x-8)(x-3)=0\\2x - 8 = 0 \ , \ x - 3 = 0\\2x = 8 \ , \ x = 3\\x = 4 , 3

6 0
3 years ago
How to find what numbers a number is divisible by
nevsk [136]
If the number ends with an even number or a number that is always divisible by 2. Or every number that ends with 5 or zero is always divisible by 5 too. Bdause for example in a fraction we do 10/5 and it will be equal to 2/1 or 2. Hope it helped you!
7 0
3 years ago
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